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weeeeeb [17]
2 years ago
6

Please refer to the following attachment and find the value of x.

Mathematics
2 answers:
Drupady [299]2 years ago
7 0

Answer:

5

Step-by-step explanation:

Sum of interior angles in a 4 sided quadrilateral is 360,

110 + 70 + 14x + 23x - 5 = 360

180 + 37x - 5 = 360

180 - 5 + 37x = 360

175 + 37x = 360

37x = 360 - 175

37x = 185

x = 185 / 37

x = 5

egoroff_w [7]2 years ago
5 0

  • ✦\bf{x=5°}✦

Step-by-step explanation:

We know that,

For a tetragon the sum of all 4 angle is 360°

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

  • 70+110+(23x-5)+14x=360

  • 180+23x-5+14x=360

  • 37x-5=360-180

  • 37x=180+5

  • 37x=185

  • x=\sf{\dfrac{185}{37} }

  • <em>x</em><em>=</em><em>5</em>
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Which graph shows a line with an x-intercept of -5?
Finger [1]

Answer:

The answer is A.

Step-by-step explanation:

The only option is A. since an intercept of (-5,0)

Option B has y-int: (0,-5)
Option C has y-int: (0,5)

Option D has x-int(5,0)

8 0
2 years ago
Aunt Kendra is pricing cakes for a baby shower she is throwing. She wants one large cake shaped like a duckling and also some cu
Andreas93 [3]

Answer:

$70

Step-by-step explanation:

Middletown Equation:

1c +50 = T

Sweet Shoppe Equation:

2c + 30 = T

Set equations equal to one another and solve for first for cupcakes then for cost.

1c + 50 = 2c + 30

c+ 20 = 2c

20 = c (twenty cupcakes would be ordered)

Now insert into either equation ( or both to check)

1(20) + 50 = 70

2(20)+ 30 = 70

Total cost would be $70

HOPE THIS HELPS!!!

4 0
2 years ago
what is the polynomial function of lowest degree with leading coefficient of 1 and roots 2 and 1 + square root2
Marta_Voda [28]
If the roots to such a polynomial are 2 and 1+\sqrt2, then we can write it as

(x-2)(x-(1+\sqrt2))

courtesy of the fundamental theorem of algebra. Now expanding yields

(x-2)(x-1-\sqrt2)=x^2-2x-(1+\sqrt2)x+2(1+\sqrt2)=x^2-(3+\sqrt2)x+2+2\sqrt2

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.

So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use 1-\sqrt2 as a root. In this case, that would make our polynomial

(x-2)(x-(1+\sqrt2))(x-(1-\sqrt2))=x^3-4x^2+3x+2

so that the answer is (probably) the third choice.

Whoever originally wrote this question should reevaluate their word choice...
5 0
3 years ago
Values of x in the inequality -3x+1&lt;7
mojhsa [17]

Answer:

The value of x is: x > -2

Step-by-step explanation:

The interval notation if you need it is (-2, ♾)

6 0
3 years ago
Write the trigonometric expression sin(sin−1u−tan−1v) as an algebraic expression in u and v. Assume that the variables u and v r
igomit [66]

Answer:

[u – v√(1 – u²)]/√(1 + v²)

Step-by-step explanation:

Let sin^-1(u) = A, therefore sinA = u.

We know that sin(theta) = opposite/hypothenuse

Therefore, sinA = u/1 and u is the opposite side to angle A while 1 is the hypotenuse. Draw an acute triangle placing u opposite to angle A and 1 as the hypotenuse. By Pythagoras theorem the adjacent would be √(1 – u²).

By doing this, it means cosA = adjacent/hypotenuse = √(1 – u²)/1 = √(1 – u²)

Also, let tan^-1(v) = B, therefore tanB = v.

We know that tan(theta) = opposite/adjacent

Therefore, tanB = v/1 and v is the opposite side to angle B while 1 is the adjacent. Draw an acute triangle placing v opposite to angle B and 1 as the adjacent. By Pythagoras theorem the hypothenuse would be √(1 + v²).

Therefore, sinB = opposite/hypotenuse = v/√(1 + v²) and cosB = adjacent/hypotenuse = 1/√(1 + v²)

Now,

sin[sin^–1(u) – tan^–1(v)] =

sin(A – B) =

sinAcosB – sinBcosA =

u[1/√(1 + v²)] – [v/√(1 + v²)][√(1 – u²)] =

[u/√(1 + v²)] – [v√(1 – u²)/√1 + v²)] =

[u – v√(1 – u²)]/√(1 + v²).

8 0
3 years ago
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