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timurjin [86]
3 years ago
8

A pendulum is hanging from a point and its total mechanical energy is 20,000 J. Neglecting friction, if energy is conserved, wha

t values should you put in the blanks.
1. At which point/s in the pendulum motion do you think is most difficult to stop?


2. At which point/s would the pendulum easiest to stop?


3. If friction were not present, how much total mechanical energy would the pendulum have at:


a. point A? _______ d. point D? ______


b. point B? _______ e. point E? ______


c. point C? _______
Physics
1 answer:
AlexFokin [52]3 years ago
5 0

(1) The pendulum will have maximum velocity at the lowest point and it will be the most difficult point to stop.

(2) Velocity at maximum height is zero and it will be the easiest point to stop the pendulum.

(3) The total mechanical energy of the pendulum would  be the same at all point.

<h3>Point of maximum velocity of the pendulum</h3>

A pendulum has maximum kinetic energy at the lowest point. The kinetic energy is given as;

K.E = ¹/₂mv²

The pendulum will have maximum velocity due to maximum kinetic energy at the lowest point and it will be the most difficult point to stop.

<h3>Point of maximum height of the pendulum</h3>

A pendulum has maximum potential energy at the highest point. The potential energy is given as;

P.E = mgh

Velocity at maximum height is zero and it will be the easiest point to stop the pendulum.

<h3>Conservation of energy</h3>

In absence of friction, the total mechanical energy will be conserved. Thus, the total mechanical energy of the pendulum would  be the same at all point.

Learn more about pendulum here:brainly.com/question/26449711

#SPJ1

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Faraday's law of induction states the following:
\varepsilon=-\frac{d\Phi}{dt}
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Knowing all this, we can conclude that the answer is C. 
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4 years ago
The airplane is flying with a constant velocity. Which force acting on the airplane below represents the friction from air resis
tankabanditka [31]

The correct answer to the question is  C i.e C represents the friction from air resistance.

EXPLANATION:

Before coming into any conclusion, first we have to understand friction.

The friction is the opposing force which acts tangentially between two bodies in contact when there is a relative motion between them.

The air resistance is that frictional force which is provided by the air to the moving body through it. Hence, the friction from air resistance will be directed opposite to the motion of the body.

In the given diagram, the airplane is going horizontally. The force A acts in forward direction while force C acts in backward direction. The forces B and D are acting vertically.  There is no motion in vertical direction. Hence, the net force of A and C will cause the airplane to move.

As the plane is moving along the direction of A, the frictional force must act along the direction of C.

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3 years ago
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Answer:

250

Explanation:

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The inclined plane in the figure above has two sections of equal length and different roughness. The dashed line shows where sec
saveliy_v [14]

The static friction exerted on the block by the incline is \mu _ s _1 Mgcos \ \theta.

The given parameters;

  • <em>mass of the block, = M</em>
  • <em>coefficient of static friction in section 1, = </em>\mu_s_1<em />
  • <em>angle of inclination of the plane, = θ</em>

<em />

The normal force on the block is calculated as follows;

Fₙ = Mgcosθ

The static friction exerted on the block by the incline is calculated as follows;

F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta

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