The airplane is flying with a constant velocity. Which force acting on the airplane below represents the friction from air resis
tance?
A
B
C
D
A
B
C
D
2 answers:
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Answer:
<h2>15m/s</h2>Explanation:
The equation for a traveling wave as expressed as y(x, t) = A cos(kx − t) where An is the amplitude f oscillation,
is the angular velocity and x is the horizontal displacement and y is the vertical displacement.
From the formula; where;
Before we can get the transverse speed, we need to get the frequency and the wavelength.
frequency = 1/period
Given period = 2/15 s
Frequency =
frequency = 1 * 15/2
frequency f = 15/2 Hertz
Given wavelength = 2m
Transverse speed
Hence, the transverse speed at that point is 15m/s
Answer:
0.50027
Explanation:
ΔA=
Where ΔA is the change in area
There is a 2 since the coefficient for area = 2 x that for the linear coefficient
is the original area
is the coefficient of thermal expansion
And T is the change in temperature
ΔA=2(0.000009)(0.5)(30-0)=0.00027
New area= ΔA+ = 0.5+0.00027=0.50027