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3241004551 [841]
1 year ago
14

A+piece+of+land+produces+an+income+that+grows+by+5%+per+annum. +if+the+first+year’s+income+is+$10,000,+what+is+the+value+of+the+

land?
Business
1 answer:
Aleonysh [2.5K]1 year ago
6 0

If a piece of land produces an income that grows by 5% per annum. The value of the land is $200,000.

<h3>Present value of the land</h3>

Using this formula

Present value=Income/Rate per annum

Let plug in  the formula

Present value=$10,000/0.05

Present value=$200,000

Therefore If a piece of land produces an income that grows by 5% per annum. The value of the land is $200,000.

Learn more about Present value of land here:brainly.com/question/14958247

#SPJ12

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Answer:

A. Differentiation strategies

Explanation:

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Elka can remember the phone number she just looked up only by repeating it over and over. When she stops saying it out loud, she
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maintenance; short-term

Explanation:

When she stops saying it out loud, she forgets it. Elka is using maintenance rehearsal to keep the information in short-term memory

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A process control system costs $200,000, has a three year service life, and a salvage value of $20,000. Find the depreciation an
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Answer:

A.

Depreciation expense each of the three years would be $60,000

Book value at the end of year 1 = $140,000

Book value at the end of year 2 =$80,000

Book value at the end of year 3 =  $20,000

B.

Depreciation expense in year 1 =$90,000

Depreciation expense in year 2 =$60,000

Depreciation expense in year 3 =$30,000

Book value at the end of year 1 =$110,000

Book value at the end of year 2 = $50,000

Book value at the end of year 3 =  $20,000

C.

Depreciation expense in year 1 = $133,333.33

Book value at the end of year 1 = $66,666.67

Depreciation expense in year 2 =  $44,444.45

Book value at the end of year 2 = $22,222.22

Depreciation expense in year 3 = $14,814.16

Book value at the end of year 3 = $7,407.40

Explanation:

Straight line depreciation expense = (Cost of asset - Salvage value) / useful life

($200,000 - $20,000) / 3 = $60,000

Depreciation expense each of the three years would be $60,000

Book value at the end of year 1 = $200,000 - $60,000 = $140,000

Book value at the end of year 2 =  $140,000 - $60,000 = $80,000

Book value at the end of year 3 = $80,000 - $60,000 = $20,000

Sum-of-the-year digits = (remaining useful life / sum of the years ) x  (Cost of asset - Salvage value)

Sum of the years = 1 + 2 + 3 = 6 years

Depreciation expense in year 1 = (3/6) x ($200,000 - $20,000) = $90,000

Depreciation expense in year 2 = (2/6) x ($200,000 - $20,000) = $60,000

Depreciation expense in year 3 = (1/6) x ($200,000 - $20,000) = $30,000

Book value at the end of year 1 = $200,000 - $90,000 = $110,000

Book value at the end of year 2 = $110,000 - $60,000 = $50,000

Book value at the end of year 3 = $50,000 - $30,000 = $20,000

Depreciation expense using the double declining method = Depreciation factor x cost of the asset

Depreciation factor = 2 x (1/useful life) = 2/3

Depreciation expense in year 1 = (2/3) x $200,000 = $133,333.33

Book value at the end of year 1 = $200,000 - $133,333.33 = $66,666.67

Depreciation expense in year 2 = (2/3) x $66,666.67 = $44,444.45

Book value at the end of year 2 = $66,666.67 - $44,444.45= $22,222.22

Depreciation expense in year 3 = (2/3) x$22,222.22 = $14,814.16

Book value at the end of year 3 =$22,222.22 - $14,814.16 = $7,407.40

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