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1 year ago

What is the domain and range of -4.92x² + 17.96x + 575

Mathematics

1 answer:

klio [65]1 year ago

6 0

The domain of the function is D ∈ R or (-∞, ∞) and the range of the function is R ∈ (591.39, ∞)

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

f(x) = -4.92x² + 17.96x + 575

The above function is a quadratic function and we know,

The quadratic function domain is all real numbers.

The domain of the function is all real numbers or

D ∈ R or (-∞, ∞)

The range:

From the graph of a function:

The maximum value of the graph:

f(1.825) = 591.39

So the range of the function:

R ∈ (591.39, ∞)

Thus, the domain of the function is D ∈ R or (-∞, ∞) and the range of the function is R ∈ (591.39, ∞)

Learn more about the function here:

brainly.com/question/5245372

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The position of an object moving along an x axis is given by x = 3.24 t - 4.20 t2 + 1.07 t3, where x is in meters and t in secon

Pavel [41]

Answer and explanation:

Given : The position of an object moving along an x axis is given by $x=3.24t-4.20t^2+1.07t^3$ where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(1)=3.24(1)-4.20(1)^2+1.07(1)^3$

$x(1)=3.24-4.20+1.07$

$x(1)=0.11$

b) At t= 2 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(2)=3.24(2)-4.20(2)^2+1.07(2)^3$

$x(2)=6.48-16.8+8.56$

$x(2)=-1.76$

c) At t= 3 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(3)=3.24(3)-4.20(3)^2+1.07(3)^3$

$x(3)=9.72-37.8+28.89$

$x(3)=0.81$

d) At t= 4 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(4)=3.24(4)-4.20(4)^2+1.07(4)^3$

$x(4)=12.96-67.2+68.48$

$x(4)=14.24$

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

$\triangle x=x(4)-x(0)$

$\triangle x=14.24-0$

$\triangle x=14.24$

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity is given by,

$\triangle x=x(4)-x(2)$

$\triangle x=14.24-(-1.76)$

$\triangle x=14.24+1.76$

$\triangle x=16$

4 0

3 years ago

PLS HELP! (it will only let me do 31 points :() but you get brainliest.

MissTica

Answer:

107, there is two lines after that so 108 109 and the last line is 110 so your answer will be 107 degrees.

Step-by-step explanation:

7 0

3 years ago

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Which of these values cannot represent the probability of an event happening?

ololo11 [35]

Answer:

Step-by-step explanation:

The last option, 1.2, cannot represent the probability of an event happening since it is more than 100% (120%). And event cannot have a higher probability of happening than "happening".

A. 0.33 is a valid response, since it represents 33%.

B. 56% is also a valid response.

C. 7/8 is also a valid response since it represents 0,875 or 87,5%.

Hope it helped,

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3 years ago

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Find the product.<br><br> (2p + 7)(3p - 9)

Yakvenalex [24]

I think the answer might be 6p^2+3p-63

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3 years ago

Help please. Thanks in advance

anygoal [31]

Since they want only the coordinates of the vertices. You only care about where the lines intersect, the greater than, less than signs are irrelevant.

Get each equation in 'y=mx+b' form
1) y = -x + 9
2) y = 2x-21
3) y = -4x +15

Now you can set any 2 equations equal to each other and solve for 'x'.
This will be the 'x' coordinate of the point where the 2 lines intersect.
You need 3 points, so you will need 3 different sets of 2 equations:

1) = 2)
2x -21 = -x+9
3x = 30
x = 10 -----> y = -(10)+9 = -1

1) = 3)
-x+9 = -4x+15
3x = 6
x = 2 -------> y = -(2) + 9 = 7

2) = 3)
2x - 21 = -4x+15
6x = 36
x = 6 ---------> y = 2(6) -21 = -9

Therefore the 3 intersecting points are:
(10,-1)
(2, 7)
(6, -9)

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3 years ago