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2 years ago

If the _ of the proteins changes, this is called a mutation

Physics

1 answer:

Delicious77 [7]2 years ago

6 0

Answer:

If the DNA of the proteins changes, this is called a mutation.

Explanation: Hope it helps you :))))

Have a good day

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On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini

irinina [24]

Answer:

$v_a=0.8176 m/s$

$\Delta K=0.07969 J - 0.0849 J = -0.00521 J$

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being $m_a$ and $m_b$ the masses of pucks a and b respectively, the initial momentum of the system is

$M_1=m_av_a+m_bv_b$

Since b is initially at rest

$M_1=m_av_a$

After the collision and being $v'_a$ and $v'_b$ the respective velocities, the total momentum is

$M_2=m_av'_a+m_bv'_b$

Both momentums are equal, thus

$m_av_a=m_av'_a+m_bv'_b$

Solving for $v_a$

$v_a=\frac{m_av'_a+m_bv'_b}{m_a}$

$v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}$

$v_a=0.8176 m/s$

The initial kinetic energy can be found as (provided puck b is at rest)

$K_1=\frac{1}{2}m_av_a^2$

$K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J$

The final kinetic energy is

$K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2$

$K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J$

The change of kinetic energy is

$\Delta K=0.07969 J - 0.0849 J = -0.00521 J$

3 0

3 years ago

true or false. because the speed of an object can change from one instant to the next, dividing the distance covered by the time

scoundrel [369]

true. Because the speed of an object can change from one instant to the next, dividing the total distance covered by the time of travel gives. average speed.

3 0

3 years ago

Read 2 more answers

What is the average reaction time of people

Yanka [14]

Answer:

the average reaction time is 0.25 seconds.

6 0

3 years ago

Read 2 more answers

Two children want to balance horizontally on a seesaw. The first child is sitting one meter to the left of the pivot point locat

Natali [406]

Answer:

d. 2m to the right of the pivot

Explanation:

m1 = m

m2 = 0.5m

d1 = 1m

d2 = ?

from principle of moment,

CWM = ACWM

m × 1 = 0.5m × d2

d2 = m/0.5m

= 1/0.5

= 2m

The 2nd child will have to sit 2m to the right

The turning effect of a force is known as the moment. It is the product of the force multiplied by the perpendicular distance from the line of action of the force to the pivot or point where the object will turn.

The principle of moments states that when in

equilibrium the total sum of the anti clockwise

moment is equal to the total sum of the

clockwise moment.

When a system is stable or balance it is said to be in equilibrium as all the forces acting on the system cancel each other out.

In equilibrium

Total Anticlockwise Moment = Total

Total Anticlockwise Moment = TotalClockwise Moment

4 0

3 years ago

a 230-newton box rests on a plank 5 meters long. One end is 1.2 meters higher than the other end. Find the components of the for

NISA [10]

Answer:

55.3 N, 223.3 N

Explanation:

First of all, we can find the angle of the inclined plane.

We have:

L = 5 m the length of the incline

h = 1.2 m is the height

We also have the relationship

$h = L sin \theta$

where $\theta$ is the angle of the incline. Solving for the angle,

$\theta= sin^{-1} (\frac{h}{L})=sin^{-1} (\frac{1.2 m}{5 m})=13.9^{\circ}$

Now we can find the components of the weight of the box, which is the force that the box exerts on the plank. Calling W = 230 N the weight of the box, we have:

- Component parallel to the incline:

$W_{par} = W sin \theta = (230 N)(sin 13.9^{\circ}) =55.3 N$

- Component perpendicular to the incline:

$W_{per} = W cos \theta = (230 N)(cos 13.9^{\circ}) =223.3 N$

4 0

3 years ago