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dalvyx [7]
3 years ago
13

What is the answer to this math problem 4-3= 8-9=

Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0

Answer:

4-3=1

8-9=-1

Step-by-step explanation:

I hope this helps

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The midpoint of line XZ is (2,-5). One endpoint is X(12,-5). Find the coordinates of the other endpoint Z
Inga [223]

Answer: (-8,-5)

Step-by-step explanation:

6 0
3 years ago
Suppose a-b=0 which one of these expressions equals ab
I am Lyosha [343]

Answer:

  E)  b^2

Step-by-step explanation:

Solving the first equation for a, we get ...

  a - b = 0

  a = b . . . . . . add b to both sides

Now, the expression ab can be rewritten as

  ab = bb = b^2 . . . . . . substitute b for a

6 0
3 years ago
5 Practice
Vladimir79 [104]

Answer:

Given - A rectangle of length 18 feet and wide 14 feet

To find - Area

Solution -

Area of rectangle = Length * Breadth

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6 0
3 years ago
16 plus 5 times a number is more than the number minus 8. Write an inequality and solve it
Radda [10]

n > -6 is the inequality for 16 plus 5 times a number is more than the number minus 8

<em><u>Solution:</u></em>

Given statement is:

16 plus 5 times a number is more than the number minus 8

We have to write a inequality

From given statement,

16 plus 5 times a number is more than the number minus 8

Let the number be "n"

Therefore,

16 plus 5 times "n" is more than "n" minus 8

Here, "plus" means addition and "minus" means subtraction and "times" means multiplication

Thus the statement is translated into inequality as:

16 + 5n >n-8

Simplify the inequality

16 + 5n >n-8\\\\\mathrm{Subtract\:}16\mathrm{\:from\:both\:sides}\\\\16 + 5n -16 > n - 8 -16\\\\5n >n-24\\\\\mathrm{Subtract\:}n\mathrm{\:from\:both\:sides}\\\\5n-n>n-24-n\\\\\mathrm{Simplify}\\\\4n>-24\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\\\frac{4n}{4}>\frac{-24}{4}\\\\n>-6

Thus the soultion is n > -6

8 0
3 years ago
An excursion group of four is to be drawn from among 5 boys and 6 girls.
tresset_1 [31]

Answer:

Because you are recounting people several times. Say for example, let us number those people

{1,2,3,4} for the four girls and {1,2…7} for the boys.

One possible combination by your way is to fix one boy and girl each, say

{1,1} and then choose the remaining people. Let this combination be, for the sake of the example, {1,1,2,2,3}. This is a valid combination.

Now, when you fix another combination of a boy and a girl, say {1,2}, you could get the same combination as before because one the combinations while choosing the three remaining people would be {1,2,3}.

A correct way would be to choose  girls and then choose 5− boys for 1≤≤4

So we get ∑4=1(4)(75−)=441

5 0
3 years ago
Read 2 more answers
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