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2 years ago

Why is it not possible to achieve a higher resolution in the light microscope?.

1 answer:

Rudiy272 years ago

3 0

Higher resolution cannot be achieved with a light microscope because wavelength of light is larger that wavelength of electrons.

<h3>What is light microscope?</h3>

Light microscope is defined as the type of microscope that makes use of visible light to magnify objects into images that can be observed.

The wavelength of light is larger than that of the electrons, therefore, higher resolution cannot be achieved with a light microscope.

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An instructor gives a demonstration in which he makes a standing wave on a long thin slinky. The slinky is 6.0 meters long. If y

Naily [24]

The characteristics of standing waves allows to find the result for the speed of the wave is:

The speed wave is: v = 10 m / s

The wave is a way of transmitting energy without mass displacement, , in the attachment we can see a diagram of the standing wave.

Each cycle corresponds to half a wavelength, they indicate that the frequency is 2.50 Hz and there are three cycles, so the wavelength is:

L = $n \frac{\lambda}{2}$

λ = 2L/n

λ = 2 6 /3

λ = 4 m

Wave speed is related to wavelength and frequency

v = λ f

v = 4 2.5

v = 10 m / s

In conclusion, using the characteristics of standing waves we can find the result for the speed of the wave is:

The wave speed is: v = 10 m / s

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3 years ago

A 0.010 kg clay ball thrown right at 16 m/s hits a marble moving left at 8.0 m/s, and sticks to it. Both move left at 3.2 m/s af

Anettt [7]

.……… it will be 7.5m/s

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3 years ago

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Newtons third lawWhat action-reaction forces are involved when a rocket engine fires? Why doesnt a rocket need air to push on? A

dangina [55]

Answer: action forc roketorce

reaction force is engine fires

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3 years ago

Determine the angular velocity ω of the telescope as it orbits around the Sun.

lara31 [8.8K]

The JWST is postioned about 1.5 million kilometers from the earth on the side facing away from the sun

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2 years ago

Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha

ikadub [295]

We have that the spring constant is mathematically given as

$k=2.37*10^{11}N/m$

Generally, the equation for angular velocity is mathematically given by

$\omega=\sqrt{k}{m}$

Where

k=spring constant

And

$\omega =\frac{2\pi}{T}$

Therefore

$\frac{2\pi}{T}=\sqrt{k}{n}$

Hence giving spring constant k

$k=m((\frac{2 \pi}{T})^2$

Generally

Mass of earth $m=5.97*10^{24}$

Period for on complete resolution of Earth around the Sun

$T=365 days$

$T=365*24*3600$

Therefore

$k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2$

$k=2.37*10^{11}N/m$

In conclusion

The effective spring constant of this simple harmonic motion is

$k=2.37*10^{11}N/m$

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