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bekas [8.4K]
1 year ago
7

Why is it not possible to achieve a higher resolution in the light microscope?.

Physics
1 answer:
Rudiy271 year ago
3 0

Higher resolution cannot be achieved with a light microscope because wavelength of light is larger that wavelength of electrons.

<h3>What is light microscope?</h3>

Light microscope is defined as the type of microscope that makes use of visible light to magnify objects into images that can be observed.

The wavelength of light is larger than that of the electrons, therefore, higher resolution cannot be achieved with a light microscope.

Learn more about microscope here:

brainly.com/question/15744335

#SPJ1

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A 1650 kg car accelerates at a rate of 4.0 m/s^2. How much force is the car's engine producing?
Westkost [7]
F = M A

Force = (mass) x (acceleration) 

                   = (1,650 kg) (4 m/s²) = 6,600 kg-m/s² = <em>6,600 Newtons</em>
7 0
3 years ago
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A storage tank containing oil (SG=0.92) is 10.0 meters high and 16.0 meters in diameter. The tank is closed, but the amount of o
blagie [28]

Answer:

a-1 Graph is attached. The relation is linear.

a-2 The corresponding height for 68 kPa Pressure is 7.54 m

a-3 The corresponding weight for 68 kPa Pressure is 1394726kg

b The original height of the column is 5.98 m

Explanation:

Part a

a-1

The graph is attached with the solution. The relation is linear as indicated by the line.

a-2

By the equation

P=\rho \times g \times h

Here

  • P is the pressure which is given as 68 kPa.
  • ρ is the density of the oil whose SG is 0.92. It is calculated as

                                       \rho=S.G \times \rho_{water}\\\rho=0.92 \times 1000 kg/m^3\\\rho=920 kg/m^3\\

  • g is the gravitational constant whose value is 9.8 m/s^2
  • h is the height which is to be calculated

                                        P=\rho \times g \times h\\h=\frac{P}{\rho \times g}\\h=\frac{68 \times 10^3}{920 \times 9.8}\\h=7.54m

So the height of column is 7.54m

a-3

By the relation of volume and density

M=\rho \times V

Here

  • ρ is the density of the oil which is 920 kg/m^3
  • V is the volume of cylinder with diameter 16m calculated as follows

                             V=\pi r^2h\\V=3.14\times (8)^2 \times 7.54\\V=1515.23 m^3

Mass is given as

                             M=\rho \times V\\M=920 \times 1515.23\\M=1394726kg

So the mass of oil leading to 68kPa is 1394726kg

Part b

Pressure variation is given as

                            \Delta P=P_{obs}-P_{atm}\\\Delta P=115-101 kPa\\\Delta P=14 kPa\\

Now corrected pressure is as

P_c=P_g-\Delta P\\P_c=68-14 kPa\\P_c=54 kPa

Finding the value of height for this corrected pressure as

P_c=\rho \times g \times h\\h=\frac{P_c}{\rho \times g}\\h=\frac{54 \times 10^3}{920 \times 9.8}\\h=5.98m

The original height of column is 5.98m

4 0
3 years ago
What is numbers 2 and 4? Please help, and many thanks to those who do chose to help.
Elan Coil [88]

Answer:

2. 6 km/h

4. 150 miles/h

5 0
2 years ago
If a 1 kg book has 46 Joules of gravitational potential energy how high is the shelf it is on?
Mashcka [7]

Answer:

4.7m

Explanation:

Given parameters:

Mass of the book  = 1kg

Gravitational potential energy  = 46J

Unknown:

Height of the shelf  = ?

Solution:

The potential energy is due to the position of a body above the ground.

        Gravitational potential energy  = mgh

m is the mass,

g is the acceleration due gravity  = 9.8m/s²

h is the height which is unknown

                       46  = 1 x 9.8 x h

                       h  = 4.7m

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Hi am not sure but have searched on online
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3 years ago
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