If a vector that is 3 cm long represents 30 km/h what velocity does a 5cm long vector which is drawn using the same scale
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The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.
<h3>What is the Inverse Square Law formula?</h3>The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as
Where
- I₁ = Intensity at distance 1 (W/m²)
- I₂ = Intensity at distance 2 (W/m²)
- d₁ = distance 1 from a light source (m)
- d₂ = distance 2 from a light source (m)
Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?
By using the inverse square law formula, the sun's intensity for an outer planet is
I₂ = 5.55 W/m²
Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².
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