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3 years ago

How can sand dunes be saved?

Physics

2 answers:

Anton [14]3 years ago

6 0

Vegetation can be planted or wooden sand fences can be in place for a healthy dune system

Margarita [4]3 years ago

5 0

Sand dunes refers to accumulation of sand grains, which is shaped into a mound by the wind. Sand dunes are first line of protection against coastal storm and beach erosion. Sand dunes destruction can be caused by many factors, but the most prominent factor is human activity. The sand dunes can be preserve and saved by planting beach grasses, erecting sand fencing, erecting and using public crossovers, keeping boats off from the sand dunes and desisting from the act of burning beach grasses.<span />

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Before leaving an incident assignment, you should do all of the following EXCEPT FOR:

Free_Kalibri [48]

<span>Self-dispatch to another incident</span>

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2 years ago

In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of1.10eVwhen light sh

V125BC [204]

5.610^-26 m is closest to the wavelength of the light.

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Because the relationship between wave frequency and wavelength is inverse, gamma rays have extremely short wavelengths that are only a fraction of the size of atoms, whereas other wavelengths can reach as far as the universe. Regardless of the medium they travel through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, even though this isn't always stated explicitly.

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8 months ago

A 1-kg iron frying pan is placed on a stove. The pan increases from 20°C to 250°C. If the same amount of heat is added to a pan

Nesterboy [21]

Answer;

The temperature change for the second pan will be lower compared to the temperature change of the first pan

Explanation;

-The quantity of heat is given by multiplying mass by specific heat and by temperature change.

That is; Q = mcΔT

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3 years ago

A ball is thrown upwards at an unknown speed. in a time of

alexandr402 [8]

Answer:

a) Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a) We have equation of motion $s=ut+\frac{1}{2} at^2$ , where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8 $m/s^2$

Substituting

$6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s$

Initial speed of the ball = 14.45 m/s

b) We have equation of motion $v^2=u^2+2as$ , where v is the final velocity

s = 6 m, u = 14.45 m/s, a = -9.8 $m/s^2$

Substituting

$v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s$

So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion $v^2=u^2+2as$ , where v is the final velocity

u = 14.45 m/s, v =0 , a = -9.8 $m/s^2$

Substituting

$0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m$

Maximum height reached = 10.65 m

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2 years ago

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2 years ago