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3 years ago

How can sand dunes be saved?

Physics

2 answers:

Anton [14]3 years ago

6 0

Vegetation can be planted or wooden sand fences can be in place for a healthy dune system

Margarita [4]3 years ago

5 0

Sand dunes refers to accumulation of sand grains, which is shaped into a mound by the wind. Sand dunes are first line of protection against coastal storm and beach erosion. Sand dunes destruction can be caused by many factors, but the most prominent factor is human activity. The sand dunes can be preserve and saved by planting beach grasses, erecting sand fencing, erecting and using public crossovers, keeping boats off from the sand dunes and desisting from the act of burning beach grasses.<span />

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Calculate the momentum of a 6 kg rock that is rolling down a hill with a velocity of 4 m/s.

Leokris [45]

Answer:

24kgm/s

Explanation:

momentum(p)=mass×velocity

=6×4

=24 kgm/s

4 0

2 years ago

It took 1500 Newton's of force to push a car 3 meters. How much work was done

denis23 [38]

Answer:

ow much work was done? W = F xD. IN X 2m = 2;. 2. A force of 15 newtons is ... 3. It took 50 joules to push a chair 5 meters across the floor. With what force was ... was done. How far was the rock lifted? W=FXD. D=1500 = 1.5m. Answer: :.5m ... A young man exerted a force of 9,000 newtons on a stalled car, but he was.

Explanation:

3 0

2 years ago

Pls help i’ll give brainliest if you give a correct answer!!

enot [183]

Answer:

the second one

Explanation:

4 0

2 years ago

One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe

Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

$\mu = \frac{m}{l}$

$\mu = \frac{8.79*10^{-3}}{70*10^{-2}}$

$\mu = 0.01255kg/m$

The expression for the wavelength of the standing wave for the second overtone is

$\lambda = \frac{2}{3} l$

Replacing we have

$\lambda = \frac{2}{3} (70*10^{-2})$

$\lambda = 0.466m$

The frequency of the sound wave is

$f_s = \frac{v}{\lambda_s}$

$f_s = \frac{344}{0.768}$

$f_s = 448Hz$

Now the velocity of the wave would be

$v = f_s \lambda$

$v = (448)(0.466)$

$v = 208.768m/s$

The expression that relates the velocity of the wave, tension on the string and linear mass density is

$v = \sqrt{\frac{T}{\mu}}$

$v^2 = \frac{T}{\mu}$

$T= \mu v^2$

$T = (0.01255kg/m)(208.768m/s)^2$

$T = 547N$

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the $n^{th}$ harmonic frequency is

$f_n = nf_1$

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

$n=3$

Then,

$f_3 = 3f_1$

Rearranging to find the fundamental frequency

$f_1 = \frac{f_3}{3}$

$f_1 = \frac{448Hz}{3}$

$f_1 = 149.9Hz$

7 0

2 years ago

If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V, the current flowing through the circ

AnnyKZ [126]

The formula for calculating the current flowing in a circuit is:
I = V /R
Where:
I = current = ?
V = voltage = 60 V
R = resistance = 12 Ohms
I = V /R = 60/ 12 = 5
Therefore, the current flowing through the circuit is 5 A.

7 0

3 years ago

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