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3 years ago

7

How can sand dunes be saved?

2 answers:

Anton [14]3 years ago

6 0

Vegetation can be planted or wooden sand fences can be in place for a healthy dune system

Margarita [4]3 years ago

5 0

Sand dunes refers to accumulation of sand grains, which is shaped into a mound by the wind. Sand dunes are first line of protection against coastal storm and beach erosion. Sand dunes destruction can be caused by many factors, but the most prominent factor is human activity. The sand dunes can be preserve and saved by planting beach grasses, erecting sand fencing, erecting and using public crossovers, keeping boats off from the sand dunes and desisting from the act of burning beach grasses.<span />

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The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal

Anon25 [30]

Answer:

$M= 0.4 Am^2$

Explanation:

From the question we are told that:

Number of turns $N=5$ $N=5$

Conductor each with side length $L=0.2m$

Current $I=2A$

Magnetic field $B=50.0T$

Generally the equation for the total magnetic moment M is mathematically given by

$M = current * area$

$M= I * A$

$M = 2 * (5* 0.2*0.2)$

$M = 2 * 0.2$

$M= 0.4 Am^2$

3 0

2 years ago

Will give correct answer brainliest

sineoko [7]

$200 \times 80\%$

<h2><em>calculate</em></h2>

<em> $200 \times \frac{80}{100}$ </em>

<h2><em>reduce </em><em>the </em><em>numbers</em></h2>

<em> $2 \times 80$ </em>

<h2><em>multiply</em></h2>

<em> $= 160$ </em>

<h2><em>there </em><em>for </em><em>we </em><em>have </em><em>a </em><em>solution</em><em> to</em><em> the</em><em> </em><em>equation</em></h2>

<em>hope </em><em>it</em><em> helps</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on</em><em> learning</em>

<em>mark </em><em>me</em><em> as</em><em> brainlist</em><em> plss</em>

6 0

2 years ago

Read 2 more answers

I need to choose a theme for my physics assignment My experiment is finding g

Kobotan [32]

<h3>Question:</h3>

How to find g (acceleration due to gravity)

<h3>Solution:</h3>

We know,

Acceleration due to gravity (g)

$= \frac{GM}{ {R}^{2} }$

where, G = Gravitational constant

$= 6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \\$

M = Mass of the earth

$= 6 \times {10}^{24} \: kg$

R = Radius of the earth

$= 6.4 \times {10}^{6} m$

Putting these values of G, M and R in the above formula, we get

$g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2}$

So, the value of acceleration due to gravity is

$9.8m/s ^{2}$

Hope it helps.

Do comment if you have any query.

5 0

2 years ago

Suppose you have a 75-watt light bulb that you leave turned on for two minutes. How much energy

victus00 [196]

Answer:

9000 J

Explanation:

Convert minutes to seconds.

2 min = 120 s

Power = energy / time

75 W = E / 120 s

E = 9000 J

5 0

2 years ago

What formula is used to calculate resistance using the color code?

jolli1 [7]

<span><em>The answer is </em><em>A</em><em> :</em><em>" R = (First digit * 10 + second digit) * multiplier. "

</em><em>yw peasant XD</em><em>
</em></span>

5 0

3 years ago