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trapecia [35]
3 years ago
13

A skydiver falls 3km in 15s. How fast are they going. i need my answer in meters! (20 PTS)

Physics
1 answer:
Alchen [17]3 years ago
8 0
Assume the skydiver falls down straight.

Then, as you ask how fast he falls, the answer will be, the speed is not constant.

The speed is proportional with gravitational acceleration g and time passes by.

In other words, v = gt = 9.8t
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· List the atomic numbers of the elements in Period 2.
PilotLPTM [1.2K]

Answer:

3,4,5,6,7,8,9,10

3. lithium

4. beryllium

5. boron

6. carbon

7. nitrogen

8. oxygen

9. fluorine

10. neon

those are the numbers in period 2 on the periodic table.

Explanation:

4 0
2 years ago
Read 2 more answers
If a 5000-kg is moving at a speed of 43 m/s, what is its momentum?
Eduardwww [97]

Answer:

215000kgm/s

Explanation:

Given parameters:

Mass of the moving body  = 5000kg

Velocity  = 43m/s

Unknown:

Momentum  = ?

Solution:

The momentum of a body is the amount of motion a body possess.

 It is mathematically expressed as:

  Momentum  = mass x velocity

 Now:

  Momentum  = 5000 x 43  = 215000kgm/s

4 0
2 years ago
Please help i need an explanation
const2013 [10]

Answer:

--

Explanation:

All potential and kinetic energy is transferred into heat. Therefore keeping the law of conservation of energy valid. No energy is created nor destroyed only changing shape.

6 0
2 years ago
If you were to be drawn into a black hole, what would happen? To the black hole, not to you.
love history [14]

Answer:

It grows

Explanation:

The blacks holes will absorb

Me hoizontally stretching me like a noodle by the spaghtification process,thus growing bigger.

7 0
3 years ago
A 1.0-μm-diameter oil droplet (density 900 kg/m3) is negatively charged with the addition of 39 extra electrons. It is released
GREYUIT [131]

Answer:

6.75\mu C/m^2

Explanation:

We are given that

Diameter,d=1\mu m=1\time 10^{-6} m

1\mu m=10^{-6} m

Radius,r=\frac{d}{2}=\frac{1}{2}\times 10^{-6}=0.5 \times 10^{-6} m

Density,\rho=900kg/m^3

Total number of electrons,n=39

Charge on electron =1.6\times 10^{-19} C

Total charge=q=ne=39\times 1.6\times 10^{-19}=62.4\times 10^{-19} C

Distance,s=2mm=2\times 10^{-3} m

Mass =density\times volume=900\times \frac{4}{3}\pi r^3=900\times \frac{4}{3}\pi(0.5\times 10^{-6})^3=4.7\times 10^{-16} kg

Initial velocity,u=0

Final speed,v=4.5 m/s

v^2-u^2=2as

(4.5)^2-0=2a(2\times 10^{-3})

20.25=4a\times 10^{-3}

a=\frac{20.25}{4\times 10^{-3}}=5062.5m/s^2

Force,F=ma

qE=ma

q(\frac{\sigma}{2\epsilon_0})=ma

\sigma=\frac{2\epsilon_0ma}{q}=\frac{2\times 8.85\times 10^{-12}\times 4.7\times 10^{-16}\times 5062.5}{62.4\times 10^{-19}}

\epsilon_0=8.85\times 10^{-12}

\sigma=6.75\times 10^{-6}C/m^2=6.75\mu C/m^2

6 0
3 years ago
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