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2 years ago

A skydiver falls 3km in 15s. How fast are they going. i need my answer in meters! (20 PTS)

1 answer:

8 0

Assume the skydiver falls down straight.

Then, as you ask how fast he falls, the answer will be, the speed is not constant.

The speed is proportional with gravitational acceleration g and time passes by.

In other words, v = gt = 9.8t

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3 years ago

The velocity of an object is the distance it travels per unit time. Suppose the velocity of a gilding bird is measured to be 52.

Elanso [62]

Answer:

$d=7.115s$

Explanation:

What problem says can be written mathematically as:

$v=\frac{d}{t}$

Where:

$v=Velocity\\t=Time\\d=Distance$

The problem itself it's really simple, we only need to replace the data provided in the previous equation, but first, let's convert the units of the velocity from cm/s to m/s because we have to work with the same units and working in meters is the most apropiate action, because is the base unit of length in the International System of Units:

$52\frac{cm}{s} *\frac{1m}{100cm} =0.52\frac{m}{s}$

Now, we can replace the data in the equation and find the time it will take the bird to travel 3.7 m:

$0.52=\frac{3.7}{t}$

Solving for t, multiplying by t both sides, and dividing by 0.52 both sides:

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3 years ago

The height of the empire state building is 318 m if a stone is dropped from the top of the building what is the stones velocity

lutik1710 [3]

79 m/s. A stone dropped from the top of the Empire State Building will have a velocity of 79 m/s just before it strikes the ground.

This problem is about free fall, to find the velocity of the stone before it strikes the ground we have to use the equation $v_{f}^{2}=v_{0}^{2}+2gh$ , the initial velocity of the stone is 0 m/s. Then:

$v_{f}^{2}=2gh$

$v_{f}=\sqrt{ 2gh}$

Solving the equation above with g = 9.8 m/s², and h = 318.0 m:

$v_{f}=\sqrt{ 2(9.8m/s^{2})(318.0m)}= 78.95 m/s$

$v_{f}$ ≅ 79 m/s

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2 years ago