Answer:
Ba(ClO₃)₂ → BaCl₂ + 3 O₂ <em>Descomposition. </em>
CaO + CO₂ → CaCO₃ <em>Combination. </em>
NaNO₂ + HCl → NaCl + HNO₂ <em>Double replacement. </em>
Mg + ZnSO₄ → MgSO₄ + Zn <em>Single replacement. </em>
Explanation:
A combination reaction is defined as a reaction in which two or more substances combine to form a single new substance.
A + B → AB
A descomposition reaction is defined as a reaction in which a compound breaks down into two or more simpler substances.
AB → A + B
A double replacement is a chemical reaction were the positive and negative ions of two ionic compounds exchange places to form two new compounds.
AB + CD → AD + CB
A single replacement is another type of reaction were one element replaces a similar element in a compound.
A + BC → AC + B
Thus, with this information it is possible to classify these reactions as:
Ba(ClO₃)₂ → BaCl₂ + 3 O₂ <em>Descomposition. </em>One single molecule breaks down into two or more molecules
CaO + CO₂ → CaCO₃ <em>Combination. </em>Two substances are combined to form one single molecule
NaNO₂ + HCl → NaCl + HNO₂ <em>Double replacement. </em>Na and H are exchange places to form two new compounds
Mg + ZnSO₄ → MgSO₄ + Zn <em>Single replacement. </em>Mg is replacing Zn.
I hope it helps!
Hydrogen chloride is polar becasue it has unequally shared electrons.
Answer:
The pressure of the gas at 23 C is 179.92 kPa.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.
Gay-Lussac's law can be expressed mathematically as follows:
Studying two states, one initial 1 and the other final 2, it is satisfied:
In this case:
- P1= 310 kPa
- T1= 237 C= 510 K (being 0 C= 273 K)
- P2= ?
- T2= 23 C= 296 K
Replacing:
Solving:
P2= 179.92 kPa
<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>
Answer:
heating point for water - 100°