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sergey [27]
3 years ago
13

What is the difference between a helium atom and an alpha particle​

Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

???????

????

Explanation:

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The rate law for the reaction 3a ⟶⟶ c is rate = 4. 36 x 10–2 l • mol–1 • h–1[ a ]2 how long will it take in hours for the concen
Paha777 [63]

The hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

<h3>What is the rate law of a reaction?</h3>

Rate law depicts the rate of a chemical reaction depend on the concentration of the reactant.

The given reaction is second order reaction

Thus, the hours taken for concentration to decrease from 0 to 74 min. to 0.21 m is 91.7 hours.

Learn more about rate law of a reaction

brainly.com/question/8314253

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4 0
2 years ago
How many moles of NaOH are in 13.25 mL of 0.323 M NaOH?
adell [148]
M=mol/L, 0.323M=mol/0.01325. Rework to solve for mol and bam! (I.e. times the two numbers)
7 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl
AlekseyPX

Answer: Concentration of NH_3 in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of H_2 = 0.729 M

The given balanced equilibrium reaction is,

                 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

Initial conc.            x                0           0

At eqm. conc.     (x-2y) M     (y) M   (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}

Now put all the given values in this expression, we get :

K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

x=0.80

concentration of NH_3 in the equilibrium mixture = 0.80-2\times 0.243=0.31

Thus concentration of NH_3 in the equilibrium mixture is 0.31 M

3 0
3 years ago
Lunar Eclipse. Choose ALL that apply
antoniya [11.8K]

Answer:

b and a i jus did it

Explanation: none

6 0
2 years ago
Read 2 more answers
Which hydrogen atom would be most easily extracted by a bromine atom?
DerKrebs [107]
The proton which is easily abstracted in 1-Benzyl-3-propylbenzene is the proton which is present on carbon atom in between two phenyl rings, or the central carbon which is shared by two benzene rings.

This easy abstraction of proton is due to its high acidity. Remember those species are always more acidic whose conjugate base is stable. Like the acidity of carboxylic acid is due to stability of the acetate ion. 

In our case the stability of conjugate base arises due to stability of negative ion due to resonance. As shown below, the negative charge can delocalize on both rings.

I have shown the resonance of negative ion on both Phenyl rings with Blue and Pink colors.<span />

4 0
3 years ago
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