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3 years ago

An element that is malleable is _____. difficult to pour easily shaped very hard very dense

1 answer:

6 0

The answer is easily shaped. Malleable means it can be shaped with ease without breaking them.
This is a common property in metals. For example, aluminum, they can be shaped into thin aluminum foil sheets because they're malleable.
In the other hand, for many non metals and semi metals, they're brittle, the opposite of malleable. They tend to break easily.

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ASAP

MissTica

Answer:4 M

Explanation:google

7 0

3 years ago

Consider the reaction of ruthenium(III) iodide with carbon dioxide and silver. RuI3 (s) 5CO (g) 3Ag (s) Ru(CO)5 (s) 3AgI (s) Det

mixer [17]

Answer:

71.6 g of Ru(CO)₅ is the maximum mass that can be formed.

The limiting reactant is Ag

Explanation:

The reaction is:

RuI₃ (s) + 5CO (g) + 3Ag (s) → Ru(CO)₅ (s) + 3AgI (s)

Firstly we determine the moles of each reactant:

169 g . 1mol /481.77g = 0.351 moles of RuI₃

58g . 1mol /28g = 2.07 moles of CO

96.2g . 1mol/ 107.87g = 0.892 moles

Certainly, the excess reactant is CO, therefore, the limiting would be Ag or RuI₃.

3 moles of Ag react to 1 mol of RuI₃

Then 0.892 moles of Ag may react to (0.892 . 1) /3 = 0.297 moles

We have 0.351 moles of iodide and we need 0.297 moles, so this is an excess. In conclussion, Silver (Ag) is the limiting.

1 mol of RuI₃ react to 3 moles of Ag

Then, 0.351 moles of RuI₃ may react to (0.351 . 3) /1 = 1.053 moles

It's ok, because we do not have enough Ag. We only have 0.892 moles and we need 1.053.

5 moles of CO react to 3 moles of Ag

Then, 2.07 moles of CO may react to (2.07 . 3) /5 = 1.242 moles of Ag.

This calculate confirms the theory.

Now, we determine the maximum mass of Ru(CO)₅

3 moles of of Ag can produce 1 mol of Ru(CO)₅

Then 0.892 moles may produce (0.892 . 1) /3 = 0.297 moles

We convert moles to mass → 0.297 mol . 241.07g /mol = 71.6 g

8 0

3 years ago

The density of a substance is 17.5 g/mL. Determine the volume (in mL) of 63.6 g of this substance.

andreyandreev [35.5K]

Answer:

<h2>volume = 3.63 mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3> $Density = \frac{mass}{volume}$ </h3>

Since we are finding the volume

Making volume the subject we have

<h3> $volume = \frac{mass}{Density}$ </h3>

From the question

mass = 63.6 g

Density = 17.5 g/mL

Substitute the values into the above formula and solve for the volume

That's

<h3> $volume = \frac{63.6}{17.5}$ </h3>

We have the final answer as

<h3>volume = 3.63 mL</h3>

Hope this helps you

5 0

3 years ago

If sugar contains 41.86 carbon and 6.98 hydrogen what percentage of sugar is oxygen

STatiana [176]

Sugar is 51.16% oxygen because 41.86 + 6.98 = 48.84, minus that from 100 gets 51.16.

8 0

3 years ago

Draw three different Lewis structures that could be possible for ZX2, assuming that Z is the central atom and that X is not hydr

Mariana [72]

Answer:

See images attached and explanation

Explanation:

I have drawn three possible structures of ZX2. We have to remember that the shapes of molecules could be predicted on the basis of the Valence shell electron pair repulsion theory.

The number of electrons on the valence shell of the central atom determines the shape of the molecule. We have also been told that X is not hydrogen.

If the two X atoms are arranged at a bond angle of 180 degrees, we could have either structure I or II. We will have these structures if the Z atom is sp2 hybridized.

Similarly, if the Z atom is sp3 hybridized, we may have structure III in which the molecule is bent with a bond angle less than 109 degrees. This may result from the presence of a lone pair on Z.

Note that all these structures obey the octet rule.

3 0

2 years ago