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2 years ago

Can be ignored, what will be the maximum height that the pendulum can

Physics

1 answer:

goldenfox [79]2 years ago

6 0

The height at point B will be 30 m. Option D is corect.

<h3 /><h3>What is simple harmonic motion?</h3>

Simple harmonic motion is a form of periodic motion in which the restoring force on a moving item is proportionate to the amount of the object's displacement.

At the highest point the kinetic energy is equal to the potential energy on the maximum height h;

$\rm mgh = \frac{1}{2} mv^2 \\\\ 2gh=v^2 \\\\\ h= \frac{v^2}{2g} \\\\\ h=\frac{14^2}{2 \times 9.81}\\\\\ h= 9.9 \ m$

The height at point B is calculated by adding the initial height to the obtained height as;

$\rm h_B = 15+9.9 \\\\ h_B = 29.9 \ m \\\\ h_B=30 \ m$

The height at point B will be 30 m.

Hence, option D is corect.

To learn more about simple harmonic motion, refer to the link brainly.com/question/17315536

#SPJ1

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3 years ago

A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy

GREYUIT [131]

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

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Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

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3 years ago

Question 4

mixas84 [53]

Answer:

it's answer is 5 kg

<h2><em>hope </em><em>it </em><em>helps </em><em>you </em></h2>

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3 years ago

Read 2 more answers

A purse at radius 2.30 m and a wallet at radius 3.45 m travel in uniform circular motion on the floor of a merry-go-round as the

ivolga24 [154]

Answer:

The acceleration of the wallet is $3\hat{i}+6\hat{j}$

Explanation:

Given that,

Radius of purse r= 2.30 m

Radius of wallet r'= 3.45 m

Acceleration of the purse $a=2\hat{i}+4.00\hat{j}$

We need to calculate the acceleration of the wallet

Using formula of acceleration

$a=r\omega^2$

Both the purse and wallet have same angular velocity

$\omega=\omega'$

$\sqrt{\dfrac{a}{r}}=\sqrt{\dfrac{a'}{r'}}$

$\dfrac{a}{r}=\dfrac{a'}{r'}$

$\dfrac{a'}{a}=\dfrac{r'}{r}$

$\dfrac{a'}{a}=\dfrac{3.45}{2.30}$

$\dfrac{a'}{a}=\dfrac{3}{2}$

$a'=\dfrac{3}{2}\times(2\hat{i}+4.00\hat{j})$

$a'=3\hat{i}+6\hat{j}$

Hence, The acceleration of the wallet is $3\hat{i}+6\hat{j}$

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3 years ago