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nevsk [136]
3 years ago
14

A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy

Physics
1 answer:
GREYUIT [131]3 years ago
8 0

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

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Your equation is:
2NaOH + H_{2}SO_{4}  ==\ \textgreater \  Na_{2}SO_{4} + H_{2}O

An equation is balanced only if there are the same number of atoms of each element on both sides of the arrow - aka same number of atoms of each element in both reactants (left of the arrow) and products (right of the arrow). 

It'll be easiest to tackle this by counting up the number of atoms of each element on the left and on the right and comparing those numbers. If there is a number in front of the entire compound, that means that number applies to all elements in the compound. If the number is a subscript (little number to the right of the element), that means that number only applies to the element that the subscript is attached to:
1) On the left, you have:
2NaOH + H_{2}SO_{4}\\
\\
Na:  \: 2 \: atoms\\
O: \: 2 + 4 = 6 \: atoms\\
H: \: 2 + 2 = 4 \: atoms\\
S:  \: 1 \: atom

2) On the right, you have:
Na_{2}SO_{4} + H_{2}O\\
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Na: \: 2 \: atoms\\ 
O: \: 4 + 1 = 5 \: atoms\\ 
H: \: 2 \: atoms\\ 
S: \: 1 \: atom

You can see that the number of oxygen and hydrogen atoms aren't equal on both the left (reactants) and the right (products), so the equation is unbalanced.

Your final answer is "T<span>he equation is unbalanced because the number of hydrogen atoms and oxygen is not equal in the reactants and in the products."</span>


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Answer:

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