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Gennadij [26K]
2 years ago
14

How many grams are in 4.5 moles of NaF?

Chemistry
1 answer:
Ilia_Sergeevich [38]2 years ago
6 0

Answer:

3139542g

Explanation:

That's because if you talk about

4.5

moles of sodium fluoride, you would get a really absurd number of grams.

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10.0 g of Mg(NO3)2 = ____ moles
JulsSmile [24]

Answer:

0.067424154568526 moles

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3 years ago
10. Lead nitrate solution mixed with sodium sulfate solution forms lead sulfate as a
Leviafan [203]

Answer:

88%.

Explanation:

The percentage yield of lead sulfate in this experiment is 88% if 2.53 is divided by 2.85 and multiply by 100. The percentage yield can be calculated when the experimental yield is divided by theoretical yield and then multiply by 100. The percentage yield tells us about the actual yield that is gained in the end of experiment which is lower than theoretical yield.

8 0
3 years ago
Tiffany was investing how fast it took Hayden to react to different sounds. Identify the independent variable.
Hatshy [7]

Answer:

The different sounds

Explanation:

since it can not be changed

7 0
3 years ago
AlCl3 + Na NaCl + Al<br><br> Did Na change oxidation number?
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3 0
3 years ago
An inhibitor is added to an enzyme-catalyzed reaction at a concentration of 26.7 μM. The Vmax remains constant at 50.0 μM/s, but
fomenos

Using the Michaelis-Menten equation competitive inhibition, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

<h3>What is the Ki for the inhibitor?</h3>

The Ki of an inhibitor is known as the inhibition constant.

The inhibition is a competitive inhibition as the Vmax is unchanged but Km changes.

Using the Michaelis-Menten equation for inhibition:

  • Kma = Km/(1 + [I]/Ki)

Making Ki subject of the formula:

  • Ki = [I]/{(Kma/Km) - 1}

where:

  • Kma is the apparent Km due to inhibitor
  • Km is the Km of the enzyme-catalyzed reaction
  • [I] is the concentration of the inhibitor

Solving for Ki:

where

[I] = 26.7 μM

Km = 1.0

Kma = (150% × 1 ) + 1 = 2.5

Ki = 26.7 μM/{(2.5/1) - 1)

Ki = 53.4 μM

Therefore, the Inhibition constant, Ki of the inhibitor is 53.4 μM.

Learn more about enzyme inhibition at: brainly.com/question/13618533

5 0
2 years ago
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