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AlladinOne [14]
3 years ago
15

Calculate % oxygen in CO (NO)3

Chemistry
1 answer:
Alexxx [7]3 years ago
8 0

50 percent

there are 8 atoms in this molecule

and 4 of them are oxygen molc. so:

\frac{4}{8}  \times 100 = \%50

good luck

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The burning of propane gas can be represented as a balanced chemical reaction as follows: C3H8(g)+5O2(g)→3CO2(g)+4H2O(g) Calcula
Snezhnost [94]

Answer: 20L of H2O

Explanation:

C3H8 + 5O2 → 3CO2 + 4H2O

Recall 1mole of a gas contains 22.4L at stp

5moles of O2 contains = 5 x 22.4 = 112L

4moles of H2O contains = 4 x 22.4 = 89.6L

From the equation,

112L of O2 produced 89.6L H2O

There for 25L of O2 will produce XL of H2O i.e

XL of H2O = (25 x 89.6)/112 = 20L

6 0
4 years ago
The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine
Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

  • Specific heat of liquid bromine (c): 0.226 J/g.K
  • Volume of bromine (V): 10.0 mL
  • Initial temperature: 25.00 °C
  • Final temperature: 27.30 °C
  • Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0
3 years ago
How many grams of KCl are present in 55.0 mL of 2.10 M KCl?
sergiy2304 [10]

Answer:

none of the above is the answer

4 0
4 years ago
Read 2 more answers
Calculate the Molar Mass in g/mol of Ammonium Sulfate, (NH4)2(SO4)
saw5 [17]

Answer:

132g/mol

Explanation:

The problem here is to find the molar mass of the compound in g/mol

To solve this problem, we simply sum the atomic masses of the atoms in the compound:

   (NH₄)₂ SO₄:

  Atomic mass of N  = 14g

   Atomic mass of H  = 1g

  Atomic mass of S  = 32g

  Atomic mass of O = 16g

So;

   Molar mass = 2[(14 + 4(1))] + 32 + 4(16)  = 132g/mol

6 0
3 years ago
If the volume of a solution is 25.6 L and its molarity is 8.20 M, how many moles of solute are
harkovskaia [24]

Answer:

210 moles

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 25.6 L

Molarity = 8.20 M

Mole of solute =?

Molarity is simply defined as the mole of solute per unit litre of water. Mathematically, it can be expressed as:

Molarity = mole /Volume

With the above formula, the mole of solute dissolved can be obtained as follow:

Volume of solution = 25.6 L

Molarity = 8.20 M

Mole of solute =?

Molarity = mole /Volume

8.20 = mole / 25.6

Cross multiply

Mole = 8.20 × 25.6

Mole = 209.92 ≈ 210 moles

Thus, the mole of solute dissolved in the solution is 210 moles

7 0
3 years ago
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