Answer:
2.48 mol/L.
Explanation:
- The molarity of the solution can be expressed as <em>the number of moles of solute in 1.0 liter of the solution, </em>(M = n / V).
- It is also can be calculated from the relation:
<em>M = (mass / molar mass) solute x (1000 / V of solution)</em>
The solute is toluene and the solvent is benzene.
mass of toluene (solute) = 57.1 g,
molar mass of toluene (solute) = 92.14 g/mol.
volume of the solution = 250 ml.
∴ M = (mass / molar mass) solute x (1000 / V of solution) = [(57.1 g / 92.14 g/mol) x (1000 / 250 ml)] = 2.48 mol/L.
Answer:
0.50 g/mL
Explanation:
Formula of Density,
D = mass / volume
Mass = 12.2 g
Volume = 54.4 mL - 30.0 mL = 24.4 mL
Putting values,
D = 12.2 g / 24.4 mL
D = 0.50 g/mL
Answer:
1s2 2s2 2p6 3s2 3p6 3d6 4s2
Explanation:
D will because water just turns from liquid to a gas by adding heat. That is a physical change. The other equations are chemical changes.
Answer
× 10²³ molecules are in 41.8 g of sulfuric acid
Explanation
The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.
Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol
Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.
Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.
Therefore, 0.426187053 moles of sulfuric acid is equal
Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.
