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GREYUIT [131]
2 years ago
13

A body starts moving from rest and attends the acceleration of 0.5m/s². calculate the velocity at the end of 3 minutes also find

the distance travelled by it during that time
​
Physics
1 answer:
puteri [66]2 years ago
4 0

Answer:

See below

Explanation:

3 minutes = 180 seconds

v f = at  =  .5 m/s^2 * 180 s =<u> 90 m/s </u>

<u />

Distance =  1/2 a t^2 = .5 * .5 * 180^2 =<u> 8100 m </u>

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Explanation:

Given

Speed of car is u=30\ m/s

Distance of the man from the car is s=55\ m

Reaction time t_r=0.5\ s

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Net effective distance to cover d=55-15=40\ m

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Require distance is more than that of net effective distance. Hence, car collides with the man.

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VashaNatasha [74]

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