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Mariana [72]
3 years ago
12

A balance is best used to measure a sample’s

Physics
1 answer:
blondinia [14]3 years ago
7 0
The answer is “ Mass “
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Which statement correctly describes the relationship between thermal energy and particle movement?
zhuklara [117]

As thermal energy increases, there is more particle movement. As thermal energy increases, there is more particle movement. As thermal energy increases, there is less particle movement.

Sure hope this helps you

5 0
2 years ago
Is there carbon atoms in the compound Ca3N2​
katen-ka-za [31]

No, there are not any carbon atoms inside this compound.

The compound is Ca_3N_2. This means there are 3 "Ca" atoms and 2 "N" atoms.

  • Ca is calcium
  • N is nitrogen

Thus, none of the elements in this compound are carbon, meaning there are no carbon atoms. Let me know if you need any clarifications, thanks!

~ Padoru

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3 years ago
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Who would win Goku Mastered Ultra Instinct 3 Kaioken X20 (And can withstand the power strain) or Shaggy using 10% of his power?
alexgriva [62]

Answer:

goku

Explanation:

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3 years ago
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1. In the laboratory, the life time of a particle moving with speed 2.8 x 10^10 cm\s is found to be 2.5 x 10^-7.
timofeeve [1]

Answer: n the laboratory, the life time of a particle moving with speed 2.8 x 10^10 cm\s is found to be 2.5 x 10^-7. Calculate the proper life of the ...

Explanation:

5 0
3 years ago
Friction provides the force needed for a car to travel around a flat, circular race track. What is the maximum speed at which a
blagie [28]

Answer:

The maximum speed at which the car can safety travel around the track is 18.6m/s.

Explanation:

Since the car is in circular motion, there has to be a centripetal force F_c. In this case, the only force that applies for that is the static frictional force f_sbetween the tires and the track. Then, we can write that:

f_s=F_c

And since f_s\leq \mu N and F_c=\frac{mv^{2}}{r}, we have:

\mu N\geq \frac{mv^{2}}{r}

Now, if we write the vertical equation of motion of the car (in which there are only the weight and the normal force), we obtain:

N-mg=0\\\\\\implies N=mg

Substituting this expression for N and solving for v, we get:

\mu mg\geq \frac{mv^{2}}{r}\\\\v\leq \sqrt{\mu gr}

Finally, plugging in the given values for the coefficient of friction and the radius of the track, we have:

v\leq \sqrt{(0.42)(9.81m/s^{2})(84.0m)}\\\\v\leq 18.6m/s

It means that in its maximum value, the speed of the car is equal to 18.6m/s.

7 0
3 years ago
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