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The volume and the mass of substance are 15cm3 and 27 gm respectively find its density

harina [27]

Answer:

$d=1.8\ g/cm^3$

Explanation:

Given that,

Mass, m = 27 grams

Volume of the substance, V = 15 cm³

We need to find the density of the substance. We know that, the density of an object is given by mass per unit volume. So,

$d=\dfrac{m}{V}\\\\d=\dfrac{27}{15}\\\\d=1.8\ g/cm^3$

So, the density of the substance is equal to $1.8\ g/cm^3$ .

8 0

3 years ago

6.7.1 Current and Current Density A sphere of radius 10 mm that carries a charge of 8 nC =8x 10°C is whirled in a circle at the

aev [14]

Answer:

Part a)

Rate of charge flow is known as electric current

Part b)

Average current flow is

$i = 4\times 10^{-7} A$

Part c)

As we know that current density is current per unit area

$j = 1.27 \times 10^{-3} A/m^2$

Explanation:

As we know that angular frequency of rotation is

$\omega = 100\pi rad/s$

now by basic definition of electric current

Part a)

Rate of charge flow is known as electric current

$i = \frac{dq}{dt}$

so here we have

$i = \frac{Q}{T}$

$i = Qf$

Part b)

here we know that

$\omega = 2\pi f$

$100\pi = 2\pi f$

$f = 50 Hz$

now we have

$i = (8\times 10^{-9})(50)$

$i = 4\times 10^{-7} A$

Part c)

As we know that current density is current per unit area

So we have

$j = \frac{i}{A}$

$j = \frac{4\times 10^{-7}}{\pi(10\times 10^{-3})^2}$

$j = 1.27 \times 10^{-3} A/m^2$

6 0

3 years ago

What is the restoring force of a spring stretched 0.35 meters with a spring contact of 55 newtons?

Vesna [10]

F=-kx = -19,25 answer D

6 0

3 years ago

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An electron has a kinetic energy of 10.1 eV. The electron is incident upon a rectangular barrier of height 18.2 eV and width 1.0

podryga [215]

Answer:

factor that the electron's probability of tunneling through the barrier increase 2.02029

Explanation:

given data

kinetic energy = 10.1 eV

height = 18.2 eV

width = 1.00 nm

wavelength = 546 nm

solution

we know that probability of tunneling is express as

probability of tunneling = $e^{-2CL}$ .................1

here C is = $\frac{\sqrt{2m(U-E}}{h}$

here h is Planck's constant

c = $\frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-10.1) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}$

c = 2319130863.06

and proton have hf = $\frac{hc}{\lambda } = {1240}{546}$ = 2.27 ev

so electron K.E = 10.1 + 2.27

KE = 12.37 eV

so decay coefficient inside barrier is

c' = $\frac{\sqrt{2m(U-E}}{h}$

c' = $\frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-12.37) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}$

c' = 1967510340

so

the factor of incerease in transmisson probability is

probability = $e^{2L(c-c')}$

probability = $e^{2\times 1\times 10^{-9} \times (351620523.06)}$

factor probability = 2.02029

3 0

3 years ago

A wire with a circular cross section has radius 0.16 mm and is lying along the x axis from x=0 to x=0.20 m. The wire is made of

kipiarov [429]

Answer:

Resistance = 68.23 Ω

Explanation:

Let's start off by remembering the fact that when resistors are connected in series, their resistances is added up to find the total resistance.

The equation for resistance using resistivity is given below:

Resistance = Resistivity * Length / Area

where Length = x

Resistivity = 3x^5

and Area = $\pi *0.00016^2$ = 8.04 * 10^(-8) meter squared

Substituting in the value of resistivity, length and area we get:

Resistance = $\frac{ (3x^5) * (x) }{(8.04*10^-^8)}$

Resistance = $\frac{ (3x^6) }{(8.04*10^-^8)}$

Since resistance in series is added, we can simply integrate this formula over the length (x = 0 to x = 0.2) to get the total resistance.

Resistance = $\int\ {\frac{ (3x^6) }{(8.04*10^-^8)}} \, dx$

Resistance = $(5.4857*10^-^6) /(8.04*10^-^8)$

Resistance = 68.23 Ω

3 0

3 years ago

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