Answer:
the radius of the earth in himalayan region is greater than terai reagion. therefore, the value of 'g' at the poles is greater than the value of g at the equator. 12
Explanation:
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Answer:
244mm
Explanation:
I₁ = 3.35A
I₂ = 6.99A
μ₀ = 4π*10^-7
force per unit length (F/L) = 6.03*10⁻⁵N/m
B = (μ₀ I₁ I₂ )/ 2πr .........equation i
B = F / L ..........equation ii
equating equation i & ii,
F / L = (μ₀ I₁ I₂ )/ 2πr
Note F/L = B = F
F = (μ₀ I₁ I₂ ) / 2πr
2πr*F = (μ₀ I₁ I₂ )
r = (μ₀ I₁ I₂ ) / 2πF
r = (4π*10⁻⁷ * 3.35 * 6.99) / 2π * 6.03*10⁻⁵
r = 1.4713*10⁻⁵ / 6.03*10⁻⁵
r = 0.244m = 244mm
The distance between the wires is 244m
Answer:
ugmd = 1/2 kx²
d = (1/2 kx²) / (ugm)
= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)
= 7.4 m
ugmd = 1/2 mv²
v = √2ugd
= √(2(0.23)(9.81 m/s²)(7.4 m)
= 5.8 m/s
Explanation:
Answer:
Range of wavelength will be 
to 
Explanation:
We have given range of frequency is 400-560 Hz
Speed of the light 
We have to find the range of the wavelength of signal transmitted
Ween know that velocity is given by 
, here 
is wavelength and f is frequency
So for 400 Hz frequency wavelength will be 
And wavelength for frequency 560 Hz 
So range of wavelength will be to
Answer:
c.Law
Explanation:
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