Ask question

Ask question

All categories

2 years ago

10

X(t)=t^2-2t+1 when does it comes to rest?

1 answer:

Hitman42 [59]2 years ago

4 0

Answer:

x(t) = t^2 - 2 t + 1 given

v = dx / dt = 2 t - 2 = 0

t = 1

It comes to rest after 1 second

You might be interested in

I place an ice cube with a mass of 0.223 kg and a temperature of −35◦C is placed into an insulated aluminum container with a mas

Nadya [2.5K]

To solve this problem it is necessary to use the calorimetry principle. From the statement it asks about the remaining ice, that is, to the point where the final temperature is 0 ° C.

We will calculate the melted ice and in the end we will subtract the total initial mass to find out how much mass was left.

The amount of heat transferred is defined by

$Q = mc\Delta T$

Where,

m = mass

c = Specific heat

$\Delta T =$ Change in temperature

There are two states, the first is that of heat absorbed by that mass 'm' of melted ice and the second is that of heat absorbed by heat from -35 ° C until 0 ° C is reached.

Performing energy balance then we will have to

$Q_i-E_h = Q_m$

Where,

$Q_ i$ = Heat absorbed by whole ice

$Q_m$ = Heat absorbed by mass

$E_h$ = Heat energy by latent heat fusion/melting

$m_i*c_i \Delta T +m*L_f = (m_wc_w+m_{al}c_{al})\Delta T$

Replacing with our values we have that

$0.223*2108(-(-35))+m*3.34*10^5 = (0.452*4186+0.553*902)(27-0)$

$16452.9+334000m = (1892.072+498.806)*27$

Rearrange and find m,

$m = 0.144Kg$

Therefore the Ice left would be

$m' = 0.223-0.144$

$m' = 0.079Kg$

Therefore there is 0.079kg ice in the containter when it reaches equilibrium

8 0

4 years ago

A sinusoidal wave travels along a stretched string. A particle on the string has a maximum speed of 2.0 m/s and a maximum accele

JulsSmile [24]

Answer:

The amplitude of the wave is 0.02 m.

Explanation:

Given that,

Maximum speed = 2.0 m/s

Maximum acceleration = 200 m/s²

We need to calculate the angular frequency

Using formula of angular frequency

$\omega=\dfrac{a_{max}}{v_{max}}$

Put the value into the formula

$\omega=\dfrac{200}{2.0}$

$\omega=100\ rad/s$

We need to calculate the amplitude of the wave

Using formula of velocity

$v_{max}=A\omega$

$A=\dfrac{v_{max}}{\omega}$

Put the value into the formula

$A=\dfrac{2.0}{100}$

$A=0.02\ m$

Hence, The amplitude of the wave is 0.02 m.

8 0

4 years ago

A radio transfers 270 j of energy electrically, 94.5 j is transferred by sound. Work out the efficiency of this radio. Give your

MakcuM [25]

Answer:

35%

Explanation:

Given data

Amount of energy transferred (Input) = 270J

Amount of energy converted to sound (Output)= 94.5J

Efficiency = output/input*100

Efficiency= 94.5/270*100

Efficiency=0.35*100

Efficiency=35%

Hence the efficiency is 35%

6 0

3 years ago

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is

Bumek [7]

Answer:

Answer is 25 kg m/s.

Explanation:

Given Data ;

mass = 0.5 kg

velocity = 10 m/s

Find ;

K.E = ?

Formula ;

KE = 1/2 mv 2

Solution:

KE = 1/2(0.5)(10)²(kg)(m/s)

=25 kg m/s

7 0

3 years ago

How long will it take to travel 200 000 m [North] traveling 10 m/s

Korvikt [17]

Answer:

there are 1,000m in a km, so 200km is 200,000m

200,000m/10m/s = 20,000s

Explanation:

Please mark me Brainlyest

4 0

3 years ago