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Dima020 [189]
3 years ago
14

Locate an example of social influence

Physics
1 answer:
lana [24]3 years ago
4 0

A student may change his or her behavior to match that of other students in a class or in the school.

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Why is learning by assimilation considered to be so effective.
emmainna [20.7K]

<span>Learning by assimilation is so effective for it involves a concise and logical approach. Most people who require clear understanding and explanation of ideas, information and abstract concepts must use this approach of learning. The reason is that, they are more attracted to logically sound theories rather than more focus on people approach and based on practical value.  </span>

In assimilating learning, people prefer readings, listening to lectures, exploring analytical models, and having time to think things through on their own. With this, all the important concept and data is clearly inculcated and stored in mind.

6 0
4 years ago
A 120-V rms voltage at 60.0 Hz is applied across an inductor, capacitor and a 100- resistor in series. If the maximum value of t
Alex787 [66]

Answer:

I_{rms} = 1.132 A

Explanation:

Given that:

A 120-V rms voltage at 60.0 Hz which applied across an inductor, capacitor and a 100- resistor in series.

If the maximum value of the current in this circuit  I_{max} =    1.60 A

what is the rms value of the current in this circuit i.e the I_{rms} = ????

The relation between  I_{max}  and  I_{rms}  can be expressed by the formula:

I_{max}   = \sqrt{2 * I_{rms}}

1.60  = 1.414 *  I_{rms}

I_{rms} =  \frac{1.60}{1.414}

I_{rms} = 1.132 A

Thus, the value of the current this circuit = 1.132 A

3 0
4 years ago
Read 2 more answers
male lions and human sprinters can both accelerate at about 10.0 m/s2. if a typical lion weighs 170 kg and a typical sprinter we
Rasek [7]

The difference in the force exerted by the ground during a race between these two species is 259.25

<h3>What is force?</h3>

Forces are influences that can change the movement of an object. A force can change the velocity of an object with mass, i.e. accelerate it. Forces can also be described intuitively by pushing or pulling. A force has both magnitude and direction and is a vector quantity.

Force exerted by the lion:

Normal force = mg

170 = m × 9.8

m = 17.34 kg

Forward force = ma

= 17.34 × 10.0

= 173.4 N

Total force = Normal force + Forward force

Total force = 170 + 173.4

= 343.4 N

Force exerted by the man:

Normal force = mg

75 = m × 9.8

m = 7.65 kg

Forward force = ma

= 7.65 × 10.0

= 76.5 N

Total force = Normal force + Forward force

Total force = 7.65 + 76.5

= 84.15 N

The difference in the forces exerted by these species is:

343.4 N - 76.5 N = 259.25 N

To know more about force visit:

brainly.com/question/19734564

#SPJ4

3 0
1 year ago
On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per
dalvyx [7]

Answer:

a) 230 Km b) 76.7 km/h c) Please see below

Explanation:

a) If we can neglect the time while the driver accelerated, the movement can be divided in two parts, each of them at a constant speed:

x = x1 + x2  \\\\x1 = 50 km/h* 1hr = 50 km, \\x2 = 90 Km/h*2hr = 180 km\\

⇒ x = 50 km + 180 km = 230 km

b) The average x component of velocity, can be calculated applying the definition of average velocity, as follows:

vavg,x = \frac{xf-xo}{t-to}

If we choose t₀ = 0 and x₀ = 0, replacing xf and t by the values we have already found, we can find vavg,x as follows:

vavg,x =\frac{230 km}{3 hr} =76.7 km/h

c) The found value of  avg,x is not the same as the arithmetic average of the initial and final values of vx (70 Km/h) due to the time traveled at both velocities was not the same.

If the driver had droven half of the time (1.5 h) at 50 km/h and the other half at 90 km/h, total displacement would have been as follows:

x = 50 km/h*1.5 h + 90 km/h*1.5 hr = 210 km

Applying the definition of average velocity once more:

vavg,x =\frac{210 km}{3 hr} =70 km/h

which is the same as the arithmetic average of the initial and final values of vₓ.

7 0
3 years ago
Two horizontal rods are each held up by vertical strings tied to their ends. Rod 1 has length L and mass M; rod 2 has length 2L
antiseptic1488 [7]

Answer:

Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.

Explanation:

For the rod 1 the angular acceleration is

\tau_1 = I_1\alpha _1 \\\\\alpha_1 = \dfrac{\tau_1}{I_1}

Similarly, for rod 2

\alpha_2 = \dfrac{\tau_2}{I_2}.

Now, the moment of inertia for rod 1 is

I_1 = \dfrac{1}{3}ML^2,

and the torque acting on it is (about the center of mass)

\tau_1 = Mg\dfrac{L}{2};

therefore, the angular acceleration of rod 1 is  

\alpha_1 = \dfrac{Mg\dfrac{L}{2}}{\dfrac{1}{3}ML^2},

\boxed{\alpha_1 = \dfrac{3g}{2L} }

Now, for rod 2 the moment of inertia is

I_2 = \dfrac{1}{3}(2M)(2L)^2

I_2 = \dfrac{8}{3} ML^2,

and the torque acting is (about the center of mass)

\tau _2 = (2M)g \dfrac{(2L)}{2}

\tau _2 = 2MgL;

therefore, the angular acceleration \alpha_2 is

\alpha_2 = \dfrac{2MgL;}{\dfrac{8}{3} ML^2,}.

\boxed{\alpha_2 = \dfrac{3g}{4L}}

We see here that

\dfrac{3g}{2L} > \dfrac{3g}{4L}

therefore

\boxed{\alpha_1 > \alpha_2.}

In other words , the initial angular acceleration for rod 1 is greater than for rod 2.

7 0
3 years ago
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