Answer:
The coordinates of the point is (0,0.55).
Explanation:
Given that,
First charge
at origin
Second charge
Second charge at point P = (0,1)
We assume that,
The net electric field between the charges is zero at mid point.
Using formula of electric field
![E=\dfrac{kq}{r^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bkq%7D%7Br%5E2%7D)
![0=\dfrac{k\times9\times10^{-6}}{d^2}+\dfrac{k\times6\times10^{-6}}{(1-d)^2}](https://tex.z-dn.net/?f=0%3D%5Cdfrac%7Bk%5Ctimes9%5Ctimes10%5E%7B-6%7D%7D%7Bd%5E2%7D%2B%5Cdfrac%7Bk%5Ctimes6%5Ctimes10%5E%7B-6%7D%7D%7B%281-d%29%5E2%7D)
![\dfrac{(1-d)}{d}=\sqrt{\dfrac{6}{9}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%281-d%29%7D%7Bd%7D%3D%5Csqrt%7B%5Cdfrac%7B6%7D%7B9%7D%7D)
![\dfrac{1}{d}=\dfrac{\sqrt{6}}{3}+1](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bd%7D%3D%5Cdfrac%7B%5Csqrt%7B6%7D%7D%7B3%7D%2B1)
![\dfrac{1}{d}=1.82](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bd%7D%3D1.82)
![d=\dfrac{1}{1.82}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B1%7D%7B1.82%7D)
![d=0.55\ m](https://tex.z-dn.net/?f=d%3D0.55%5C%20m)
Hence, The coordinates of the point is (0,0.55).
Answer:
El neumático soportará una presión de 1.7 atm.
Explanation:
Podemos encontrar la presión final del neumático usando la ecuación del gas ideal:
![PV = nRT](https://tex.z-dn.net/?f=%20PV%20%3D%20nRT%20)
En donde:
P: es la presión
V: es el volumen
n: es el número de moles del gas
R: es la constante de gases ideales
T: es la temperatura
Cuando el neumático soporta la presión inicial tenemos:
P₁ = 1.5 atm
T₁ = 300 K
(1)
La presión cuando T = 67 °C es:
(2)
Dado que V₁ = V₂ (el volumen del neumático no cambia), al introducir la ecuación (1) en la ecuación (2) podemos encontrar la presión final:
Por lo tanto, si en el transcurso de un viaje las ruedas alcanzan una temperatura de 67 ºC, el neumático soportará una presión de 1.7 atm.
Espero que te sea de utilidad!
Answer:
As the tines of the tuning fork vibrate at their own natural frequency, they created sound waves that impinge upon the opening of the resonance tube. These impinging sound waves produced by the tuning fork force air inside of the resonance tube to vibrate at the same frequency.
True, because it is the state between solid and liquid
Answer:
A) 138.8g
B)73.97 cm/s
Explanation:
K = 15.5 Kn/m
A = 7 cm
N = 37 oscillations
tn = 20 seconds
A) In harmonic motion, we know that;
ω² = k/m and m = k/ω²
Also, angular frequency (ω) = 2π/T
Now, T is the time it takes to complete one oscillation.
So from the question, we can calculate T as;
T = 22/37.
Thus ;
ω = 2π/(22/37) = 10.5672
So,mass of ball (m) = k/ω² = 15.5/10.5672² = 0.1388kg or 138.8g
B) In simple harmonic motion, velocity is given as;
v(t) = vmax Sin (ωt + Φ)
It is from the derivative of;
v(t) = -Aω Sin (ωt + Φ)
So comparing the two equations of v(t), we can see that ;
vmax = Aω
Vmax = 7 x 10.5672 = 73.97 cm/s