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3 years ago

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is

Physics

1 answer:

Bumek [7]3 years ago

7 0

Answer:

Answer is 25 kg m/s.

Explanation:

Given Data ;

mass = 0.5 kg

velocity = 10 m/s

Find ;

K.E = ?

Formula ;

KE = 1/2 mv 2

Solution:

KE = 1/2(0.5)(10)²(kg)(m/s)

=25 kg m/s

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3 years ago

A 100-turn, 2.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 60∘ away from vertical increases fro

bixtya [17]

Answer:

The induced emf is $|\epsilon|=0.0261 V$

Explanation:

From the question we are told that

The number of turn is $N = 100$

The diameter of the coil is $d = 2.0 cm = 2.0 *10^{-2} m$

The uniform magnetic at initial is $B_i = 0.50 T$

The uniform magnetic at initial is $B_f = 1.50 T$

The time taken is $t = 0.60s$

The angle the magnetic field makes with vertical is $\theta = 60^o$

Generally induced emf is mathematically represented as

$\epsilon = -N \frac{d \o}{dt}$

where $d \o$ is the change magnetic flux

Magnetic flux is mathematically represented as

$\O = \= B \cdot \= A$

$= BA cos \theta$

Substituting this above

$\epsilon = -N \frac{d (BA cos \theta)}{dt}$

$\epsilon = -N A \frac{d (B cos \theta)}{dt}$

Where B is the magnetic field and A is the area which is mathematically evaluated as

$A = \frac{\pi d^2}{4}$

Substituting values

$A = \frac{\pi (2.0 *10^{-2})^2}{4}$

$A= 3.142*10^{-4}m^2$

From the equation of emf

$\epsilon = -N A \frac{d (B cos \theta)}{dt}$

dB = $B_2 -B_1$

$|\epsilon| = N A \frac{ (B_2 -B_1 cos \theta)}{dt}$

substituting values

$|\epsilon| = 100(3.142*10^{-4}) \frac{ (1.50 -0.50 cos(60))}{0.60}$

$|\epsilon|=0.0261 V$

6 0

3 years ago

Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni

sweet-ann [11.9K]

Answer:

d) 1/4 F

Explanation:

The magnitude of electrostatic force between stationary charges is described by Coulomb's law. This law states that this force is proportional to the magnitudes of the charges:

$F\propto q_1q_2$

When each of the spheres has lost half its initial charge, we have:

$q_1'=\frac{q_1}{2}\\q_2'=\frac{q_2}{2}$

So, the new electrostatic force is:

$F'\propto q_1'q_2'\\F'\propto \frac{q_1}{2}\frac{q_2}{2}\\F'\propto \frac{q_1q_2}{4}\\F'\propto\frac{1}{4}F$

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3 years ago

A tractor ploughing a field accelerates at 2 m/s2

Helen [10]

Answer:

3 m/s

Explanation:

Given:

a = 2 m/s²

Δx = 10 m

v = 7 m/s

Find: v₀

v² = v₀² + 2a (x − x₀)

(7 m/s)² = v₀² + 2 (2 m/s²) (10 m)

v₀ = 3 m/s

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3 years ago

Am 1 years old UwU (JK 15)

igomit [66]

Answer:

so am i ._. 15 not 1 ofc lol

Explanation:

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3 years ago