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miskamm [114]
3 years ago
15

Can you use division to solve a missing factor problem

Mathematics
1 answer:
klasskru [66]3 years ago
5 0
Yes, you can use division to solve a missing factor problem
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The number of students enrolled at a community
LenKa [72]
Please include a picture!!!!
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3 years ago
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


3 0
3 years ago
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Find the area of a circle with a diameter of four
Elis [28]

Answer:

12.57

Step-by-step explanation:

the formula for the area of a circle is \pi r^{2}

the diameter is 2 times the radius, so dividing it by 2 gives you a radius of 2

substitute the 2 for the r in the formula and solve

\pi 2^{2}

4\pi

≈12.57

7 0
3 years ago
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Seattle, wa and san francisco, ca lie on the same longitudinal line. san francisco is at 38° latitude and seattle is at 47° lati
Varvara68 [4.7K]

Step 1.

Calculate measure of angle α:

47^o-38^o=9^o

Step 2.

Calculate what fraction of the angle 360° ​​is the angle α:

\dfrac{9^o}{360^o}=\dfrac{1}{40}

Step 3.

Calculate the circumference of the Earth (circle):

C=2\pi r\to C=2\pi\cdot4000=8000\pi\ mi

Step 4.

The length of arc is equal 1/40 of the circumference:

\dfrac{1}{40}C=\dfrac{1}{40}\cdot8000\pi=200\pi\ mi

\pi\approx3.14\to\dfrac{1}{40}C\approx200\cdot3.14=628\ mi


<h3>Answer: A) 628 miles</h3>

8 0
3 years ago
PLEASE HELP!!!
Salsk061 [2.6K]
Triangular
I think that it
4 0
3 years ago
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