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Mamont248 [21]
1 year ago
8

you are give a bottle that contains 4.59cm3 of a metalic solid .the total mass of the bottle plus solid =35.66g .the empty bottl

e weighs 14.23g .what is the density of the solid
Chemistry
1 answer:
kirill115 [55]1 year ago
6 0

Answer:

Density = 4.67 g/cm³

Explanation:

Density can be found using the following formula:

Density = mass (grams) / volume (cm³)

The mass of the solid can be found by subtracting the weight of the empty bottle from the weight of the bottle + solid.

35.66 g - 14.23 g = 21.43 g solid

Now that you have the volume and mass, you can determine the density via the formula.

Density = mass / volume

Density = 21.43 g / 4.59 cm³

Density = 4.67 g/cm³

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Which color would have the shortest wavelength?!<br>A) red<br>B) yellow<br>C) green<br>D)blue
aliya0001 [1]
D) blue

(about 400 nanometers)
8 0
3 years ago
You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8
Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is pK_a  =7.82

Explanation:

From the question we are told

    The volume of base is  V_B = 26.mL = 0.0260L

     The pH of solution is  pH =  7.82

      The concentration of the acid is C_A = 0.1M

From the pH we can see that the titration is between a strong base and a weak acid

 Let assume that the the volume of acid is  V_A = 18mL= 0.018L

Generally the concentration of base

                    C_B = \frac{C_AV_A}{C_B}

Substituting value  

                     C_B = \frac{0.1 * 0.01800}{0.0260}

                    C_B= 0.0692M

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

           HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}

Now before the reaction the number of mole of base is  

            No \ of \ moles[N_B]  =  C_B * V_B

Substituting value  

                    N_B = 0.01300 * 0.0692

                         = 0.0009 \ moles    

                                 

Now before the reaction the number of mole of acid is  

            No \ of \ moles  =  C_B * V_B

Substituting value  

                    N_A = 0.01800 *0.1

                         = 0.001800 \ moles

Now after the reaction the number of moles of  base is  zero  i.e has been used up

    this mathematically represented as

                         N_B ' = N_B - N_B = 0

    The  number of moles of acid is  

             N_A ' = N_A  - N_B

                   = 0.0009\ moles

The pH of this reaction can be mathematically represented as

                 pH  = pK_a + log \frac{[base]}{[acid]}

Substituting values

                  7.82 = pK_a +log \frac{0.0009}{0.0009}

                  pK_a  =7.82        

                     

             

                                 

       

           

                     

8 0
2 years ago
From 1962 until 1981 pennies were made from 95% copper and 5% zinc and had a mass of 3.1 g. Starting in 1982, pennies have been
Sloan [31]

Answer:

2.7724 g

Explanation:

Mass of pre- 1892 pennies = 3.1 g

Abundance = 45.4 %

Mass of post 1892 pennies = 2.5 g

Abundance = 100 - 45.4 = 54.6 %

The average mass is given as = ( 3.1 g   *  45.4 / 100)  +  (2.5g  *  54.6 / 100)

Average Mass = 3.1 * 0.454   +   2.5  *  0.546

Average Mass = 1.4074  + 1.365 = 2.7724 g

8 0
3 years ago
Which of the following pairs contains a conjugate acid-base pair?
zzz [600]
Remember that a conjugate acid-base pair will differ only by one proton. 
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An example of a conjugate acid-base pair would be NH₃ and NH₄⁺NH₃ + H₂O --> NH₄⁺ + OH⁻NH3 is the base, and NH₄⁺ is the conjugate acid
5 0
3 years ago
Which of the following statements describes sound energy?
Galina-37 [17]

Answer:

C.

Explanation:

8 0
2 years ago
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