All categories

3 years ago

A mixture of reactants and products for the reaction shown below is at

Chemistry

1 answer:

12345 [234]3 years ago

8 0

Answer:

D. The concentrations of N2, H2, and NH3 would remain the same.

Explanation:

In reversible reactions, equilibrium is a point in which the rate of forward reaction is equal to that of reverse reaction.
Given the equation;

N₂(g)+ 3H₂(g) → 2NH₃(g) is a equilibrium at a constant volume of 1.0 L

Addition of Argon gas which an inert gas dose not affect the equilibrium of the reaction.
This is because the addition of an inert gas at constant volume only causes an increase in the total pressure of the system while the concentrations of the reactants and products remain constant, therefore not affecting the equilibrium.

You might be interested in

The object whose motion is shown on the following graph is

Tanzania [10]

I don’t understand what your asking please explain more

8 0

3 years ago

A 6.00 L vessel contains 20.0 g of PCl3 and 3.15 g of O2 at 15.0 ∘C. The vessel is heated to 210 ∘C, and the contents react to g

dusya [7]

Answer: The final pressure in the vessel will be 0.965 atm

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For phosphorus trichloride:

Given mass of phosphorus trichloride = 20.0 g

Molar mass of phosphorus trichloride = 137.3 g/mol

Putting values in equation 1, we get:

$\text{Moles of phosphorus trichloride}=\frac{20.0g}{137.3g/mol}=0.146mol$

For oxygen gas:

Given mass of oxygen gas = 3.15 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{3.15g}{32g/mol}=0.098mol$

The chemical equation for the reaction of phosphorus trichloride and oxygen gas follows:

$2PCl_3+O_2\rightarrow 2POCl_3$

By Stoichiometry of the reaction:

2 moles of phosphorus trichloride reacts with 1 mole of oxygen gas

So, 0.146 moles of phosphorus trichloride will react with = $\frac{1}{2}\times 0.146=0.073mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, phosphorus trichloride is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of phosphorus trichloride produces 2 moles of $POCl_3$

So, 0.146 moles of phosphorus trichloride will produce = $\frac{2}{2}\times 0.146=0.146mol$ of $POCl_3$

To calculate the pressure of the vessel, we use the equation given by ideal gas follows:

$PV=nRT$

where,

P = pressure of the vessel = ?

V = Volume of the vessel = 6.00 L

T = Temperature of the vessel = $210^oC=[210+273]K=483K$

R = Gas constant = $0.0821\text{ L. atm }mol^{-1}K^{-1}$

n = number of moles = 0.146 moles

Putting values in above equation, we get:

$P\times 6.00L=0.146mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 483K\\\\P=\frac{0.146\times 0.0821\times 483}{6.00}=0.965atm$

Hence, the final pressure in the vessel will be 0.965 atm

3 0

3 years ago

Read 2 more answers

What volume of oxygen in liters at STP wpuld be required for the combustion of 17.0 grams PH3?

Lynna [10]

First, we need to state the chemical equation for the combustion of PH3

$4PH3\text{ + 8O2 }\to\text{ P4O10 }+6H2O$

And the mass of PH3 is 17.0 grams and we need to know the moles.

In the periodic table, the atomic mass of the P (phosphorus) is 31 and the atomic mass of the H (hydrogen) is 1.

So, you sum the mass of P to the mass of H multiplied by 3 and you obtain this:

$\text{mole}cu\text{lar weight of PH3=31}\cdot1+1\cdot3=34\text{ g PH3/mol}$

With this data, we can search the moles of PH3:

7 0

1 year ago

Taylor, a MIC 206 student needs to determine the OCD of a sample of Escherichia coli. She performed dilutions using four 9 ml di

Troyanec [42]

Answer:

1.37 x $10^6$ CFU/mL

Explanation:

First, the dilution factor needs to be calculated.

Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of $10^{-4}$ .

Next is to divide the colony forming unit from the dilution by the dilution factor:

137/ $10^{-4}$ = 137 x $10^4$

In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.

137 x $10^4$ /1 = 1.37 x $10^6$

Hence, the CFU/ml present in the original E. coli  sample is 1.37 x $10^6$ .

cfu/ml = (no. of colonies x dilution factor) / volume of culture plate

7 0

3 years ago

Between magnesium and calcium, which has the highest ionization energy, and why?

quester [9]

Answer:

magnesium

Explanation:

magnesium has fewer valence shells meaning that the protons have a stronger hold on the electrons and it would take more energy to remove an electron to create an ion.

3 0

3 years ago