Answer:

Explanation:
Molarity is found by dividing the moles of solute by liters of solution.

We know the molarity is 1.2 M (mol\liter) and there are 2.3 liters of solution. Substitute the known values into the formula.

Since we are solving for x, we must isolate the variable. It is being divided by 2.3 and the inverse of division is multiplication. Multiply both sides by 2.3 liters.

In a solution with a molarity of 1.2 and 2.3 liters of solution, there are 2.76 moles.
1) acid
2) ether
3) ester
4) aldehyde
5) ketone
6) amine
7) alcohol
Answer:
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Explanation:
Yup go this website for more information http://dwb.unl.edu/calculators/activities/BalEqn.html
Answer:1. ![Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=Rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. The rate constant (k) for the reaction is 
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
![rate=k[CHCl_3]^x[Cl_2]^y](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5Ex%5BCl_2%5D%5Ey)
k= rate constant
x = order with respect to 
y = order with respect to 
n = x+y= Total order
1. a) From trial 1:
(1)
From trial 2:
(2)
Dividing 2 by 1 :![\frac{0.0069}{0.035}=\frac{k[0.020]^x[0.010]^y}{k[0.010]^x[0.010]^y}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0069%7D%7B0.035%7D%3D%5Cfrac%7Bk%5B0.020%5D%5Ex%5B0.010%5D%5Ey%7D%7Bk%5B0.010%5D%5Ex%5B0.010%5D%5Ey%7D)
therefore x=1.
b) From trial 2:
(3)
From trial 3:
(4)
Dividing 4 by 3:
therefore 
![rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}](https://tex.z-dn.net/?f=rate%3Dk%5BCHCl_3%5D%5E1%5BCl_2%5D%5E%5Cfrac%7B1%7D%7B2%7D)
2. to find rate constant using trial 1:
