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2 years ago

Which of the compounds below will ionize in

Chemistry

2 answers:

VMariaS [17]2 years ago

6 0

The answer should SO2

-BARSIC- [3]2 years ago

5 0

I need help on this one

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Help help help pls pls pls

Arlecino [84]

Explanation:

Aluminium and Chlorine.

Al and Cl2.

4 0

2 years ago

12.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?

Zielflug [23.3K]

Answer: 7.693 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=0.63atm\\V_1=12.70L\\P_2=105kPa=1.04atm(1kPa=0.009atm)\\V_2=?$

Putting values in above equation, we get:

$0.63\times 12.70mL=1.04\times V_2\\\\V_2=7.693L$

Thus new volume of the gas is 7.693 L

6 0

3 years ago

Read 2 more answers

Consider the following electron configurations to answer the questions that follow: (i) 1s2 2s2 2p6 3s1 (ii) 1s2 2s2 2p6 3s2 (ii

Ahat [919]

Option (i) would have the highest 2nd Ionization Energy.

Option (i) is Sodium.

Can be Written as 2, 8 , 1

For its 1st Ionization energy... It'd be extremely easy to remove that Electron cos its on the outermost shell.

Now After Removing that Electron...

Sodium's Electronic Configuration Reduces to that of Neon Which is 2, 8.

Neon has a very stable Octet.

It would take an ENORMOUS amount of energy to break its Octet stability... that is... Remove 1 electron from its Octet.

Option (i) [Sodium] has the highest 2nd Ionization Energy

6 0

2 years ago

What is the mass number of an atom or ion with three protons, three neutrons, and three electrons?.

____ [38]

Answer:

the mass number of the atom or ion is 6

5 0

3 years ago

calculate the number of moles of sulfuric acid that is contained in 250 mL of 8.500 M sulfuric acid solution

san4es73 [151]

Answer : The moles of $H_2SO_4$ are, 2.125 mole.

Explanation : Given,

Molarity of $H_2SO_4$ = 8.500 M

Volume of solution = 250 mL = 0.250 L (1 L = 1000 mL)

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Moles of }H_2SO_4}{\text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$8.500M=\frac{\text{Moles of }H_2SO_4}{0.250L}$

$\text{Moles of }H_2SO_4=2.125mol$

Therefore, the moles of $H_2SO_4$ are, 2.125 mole.

5 0

2 years ago