Answer:
The masses of the reactants and products are equal.
Explanation:
Hope this helps.
Moles of Bromine produced = 9 moles
<h3>Further explanation</h3>
Given
9 moles of Chlorine gas
Word equation
Required
Moles of Chlorine produced
Solution
We change the word equation into a chemical equation (with a formula)
Aluminum bromide reacts with chlorine gas to produce Aluminum chloride and bromide gas
2AlBr₃+3Cl₂⇒2AlCl₃+3Br₂
moles Cl₂ = 9
Maybe you mean, <em>how many moles of Bromine can we produce?</em>
From equation, mol ratio Cl₂ : Br₂ = 3 : 3, so mol Br₂=mol Cl₂=9 moles
Answer:
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions.
Explanation:
The student have in solution Ag⁺ and Cu²⁺ ions but he just want to analyze the silver, that means he need to separate ions.
Centrifuging the solution to isolate the heavier ions <em>FALSE </em>Centrifugation allows the separation of a suspension but Ag⁺ and Cu²⁺ are both soluble in water.
Adding enough base solution to bring the pH up to 7.0 <em>FALSE </em>At pH = 7,0 these ions are soluble in water and its separation will not be possible.
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions <em>TRUE </em>For example, the addition of Cl⁻ will precipitate the Ag⁺ as AgCl(s) allowing its separation.
Evaporating the solution to recover the dissolved nitrates. <em>FALSE</em> . Thus, you will obtain the nitrates of these ions but will be mixed doing impossible its separation.
I hope it helps!
Answer:
1) Basic
2) Basic
3) Acidic
Explanation:
pH of a solution is a measure of the H3O+ ions in the solution and hence reflects its acidity.
![pH = -log[H3O+]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH3O%2B%5D)
Solutions are classified as acidic, basic or neutral based on the pH range
-pH < 7, acidic
- pH = 7, neutral
- pH > 7, basic
1) [H3O+] = 2.5*10^-9M
![pH = -log[H3O+]=-log[2.5*10^{-9}]=8.60](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH3O%2B%5D%3D-log%5B2.5%2A10%5E%7B-9%7D%5D%3D8.60)
Since pH > 7, solution is basic
2)[OH-] = 1.6*10^-2M
![pOH = -log[OH-]=-log[1.6*10^{-2}]=1.80](https://tex.z-dn.net/?f=pOH%20%3D%20-log%5BOH-%5D%3D-log%5B1.6%2A10%5E%7B-2%7D%5D%3D1.80)
pH = 14 - pOH = 14 - 1.80 =12.2
Since pH > 7, solution is basic
3) [H3O+] = 7.9*10^-3M
![pH = -log[H3O+]=-log[7.9*10^{-3}]=2.10](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH3O%2B%5D%3D-log%5B7.9%2A10%5E%7B-3%7D%5D%3D2.10)
Since pH < 7, solution is acidic
The mole fraction of pentane in the vapor is 0.291
Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.
The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.
Using the formula for vapour pressure,
vapour pressure =
°
×
+
°
× 
vapour pressure = 151 × 

+ 425 × 
240 = 151 - 151
+ 425
240 - 151 = - 151
+ 425 
89 = 274 
= 
0.291 = 
Therefore, the mole fraction of pentane in the vapor is 0.291
Learn more about vapour pressure here;
brainly.com/question/25699778
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