Ask question

Ask question

All categories

PilotLPTM [1.2K]

2 years ago

10

How do I convert 4,500mm to a m

1 answer:

marissa [1.9K]2 years ago

6 0

K h d m d c m

If you move the decimal from the very right m (mm) to the left until you get to the middle m (meters) you have your answer.

You would move the decimal 3 times to the left because it is going from small to big so the number gets smaller. The answer is simply 4.5 m. You can use this tool with any of the units (liter, meter, gram) the metric system is all based off of 10. If you are going to big to small you would move the decimal to the right and add 0’s if needed.

You might be interested in

WILL MARK BRAINIEST! 18 POINTS! NEED IN 15 MINUTES!

rusak2 [61]

Answer:

the answer is lungs

Explanation:

All of the animals from frogs and up have and use lungs.

8 0

3 years ago

A blank observation is when you describe something

lana [24]

The correct answer would be... Scientific

8 0

3 years ago

based on your observation, you can infer that thermal energy transfers to/from objects with higher temperatures to/from objects

BlackZzzverrR [31]

Answer:

1. from 2. to

Explanation:

6 0

3 years ago

What type of element is most abundant: metals, nonmetals, or metalloids?

AnnyKZ [126]

Metals are the most abundant

7 0

3 years ago

Read 2 more answers

What is the osmotic pressure of a solution made from 22.3 g of methanol (MM = 32.04 g/mol) that was added to water to make 321 m

xxMikexx [17]

Answer: The osmotic pressure of a solution is 53.05 atm

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (methanol) = 22.3 g

Volume of solution = 321 mL

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K$

$\pi=53.05atm$

Hence, the osmotic pressure of a solution is 53.05 atm

7 0

2 years ago