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alexgriva [62]
3 years ago
11

Magneisum and Bromine formation

Chemistry
1 answer:
Elenna [48]3 years ago
3 0

Answer:

Magnesium and bromine will form MgBr2, a.k.a. 79.904 Glossary. Therefore, the proper formula for this ionic compound is MgO. Members of a group typically have similar properties and electron configurations in their outer shells.

Explanation:

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Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh
Dima020 [189]

<u>Answer:</u> The \Delta G^o for the given reaction is -7.84\times 10^4J

<u>Explanation:</u>

For the given chemical reaction:

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Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V  ( × 2)

<u>Reduction half reaction:</u> Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V

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To calculate the E^o_{cell} of the reaction, we use the equation:

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To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

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Putting values in above equation, we get:

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Explanation:

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