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2 years ago

How do u calculate pythagoras therorem

Mathematics

2 answers:

Katyanochek1 [597]2 years ago

7 0

The Pythagorean Theorem is basically a way to find the side of a right triangle from the other two sides.

Take a look at this triangle labeled, a, b, c. (attachment)

Side a and b are called the legs. The largest side, c is called the hypotenuse.

In order to find a side, we have to use the formula…

a^2 + b^2 = c^2

Let’s do an example.

Consider the following triangle.

(attachment)

We want to find side c, which is actually the hypotenuse as it is unknown.

In order to find the missing side, we have to use the formula or the Pythagorean theorem. We substitute our values into a and b, while leaving the c-side as it is because that is what we are trying to find.

[Math Processing Error]

What does 13=c mean? It means that the missing side, c, from the triangle above is 13.

Kamila [148]2 years ago

4 0

Answer:

a^2+b^2=c^2

Step-by-step explanation:

You can apply this formula to any quadratic equation.

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3 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago

Can someone help me with this?

NikAS [45]

my brother did that too but I'm sorry i cant help you but I'm gonna say just keep up the good work

3 0

3 years ago

Factor the expression completely:<br> 2x² + 5x - 12

Finger [1]

Using the slip and slide method:

2x^2+5x-12
x^2+5x-24
(x+8)(x-3)

(x+8/2)(x-3/2)
(x+4)(2x-3)

Final answer: (2x-3)(x+4)

7 0

3 years ago

Read 2 more answers

Q6 Q20.) Solve the equation for x in the interval [0,2π).

Marysya12 [62]

Hello there!

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8 0

3 years ago