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2 years ago

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HELP ME PLS "A school is planning for an addition in some open space next to the current building. The existing building ends at

the origin. The graph represents the system of equations that can be used to define the space for the addition. What is the system of equations that matches the graph?"

1 answer:

fgiga [73]2 years ago

4 0

Answer:

y ≤ 3x

y > - 2x - 1

(1st choice)

Step-by-step explanation:

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Tell me the anwser and explain it

lina2011 [118]

Hi there!

If KLM is an isosceles triangle, then KM = LM.

4d - 13 = 12 - d

Solve for d. Add 'd' to both sides:

5d - 13 = 12

Add 13 to both sides:

5d = 25

Divide both sides by 5:

<u>d = 5 units.</u>

3 0

2 years ago

In a sewage treatment plant, a large concrete tank initially contains 440,000 liters of liquid and 10,000 kg of fine suspended s

viva [34]

Answer:

$Concentration = 8.26kg/m^3$

Step-by-step explanation:

Given

$V = 440000L$ --- volume of tank

$m = 10,000 kg$ --- solid mass

$r = 40000L/hr$ --- outflow rate

Required

Determine the concentration at the end of 4 hours

First, calculate the amount of liquid that has been replaced at the end of the 4 hours.

$Amount = r * Time$

$Amount = 40000L/hr * 4hr$

$Amount = 40000L * 4$

$Amount = 160000L$

This implies that, over the 4 hours; The tank has 160000 liters of liquid out of 440000 liters were replaced

Calculate the ratio of the liquid replaced.

$Ratio = \frac{Amount}{Volume}$

$Ratio = \frac{160000L}{440000L}$

$Ratio = \frac{16}{44}$

$Ratio = \frac{4}{11}$

Next, calculate the amount of solid left.

$Amount (Solid)= Ratio * m$

$Amount (Solid)= \frac{4}{11} * 10000kg$

$Amount (Solid)= \frac{40000}{11}kg$

$Amount (Solid)= 3636kg$

Lastly, the concentration is calculated as:

$Concentration = \frac{Amount (Solid)}{Volume}$

$Concentration = \frac{3636kg}{440000L}$

Convert L to cubic meters

$Concentration = \frac{3636kg}{440000* 0.001m^3}$

$Concentration = \frac{3636kg}{440m^3}$

$Concentration = 8.26kg/m^3$

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3 years ago

Solve the equation. <br> 15x^2 – 28x + 5 = 0

stiv31 [10]

Answer:

Step 1: Factor left side of equation.

(5x−1)(3x−5)=0

Step 2: Set factors equal to 0.

5x−1=0 or 3x−5=0

x=

1 /5

or x=

5 /3

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Mrac [35]

The awnser is the simplified stystem is the arbitrary solution of the original system of equations

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