One of the numbers is 40 and the other one is 63
confirmation:
63×(2/3)-2=40
and 40+63=103
Answer:
64
Step-by-step explanation:
The surface of the triangle count formula
A = b*h*1/2
A - area
b - base
c - height
The first triangle
A₁ = b₁*h = 6in * 8in *1/2= 24in²
The second triangle
A₂ b₂*h = 10in * 8in*1/2 = 40in²
The total area of the two triangles is 24in² + 40in² = 64 square inches
25 I'm guessing because half of 50 IS 25. So 25 sq m should be the answer.
Answer: The answers is (B) equal areas.
Step-by-step explanation: Given that two triangles have equal perimeters.
As shown in the attached figure, let us consider two right-angles triangles, ΔABC and ΔDEF, with sides AB = 3 cm, BC = 4 cm, AC = 5 cm, DE = 4 cm, EF = 3 cm and DF = 5 cm.
So the perimeters of both the triangles = 3 + 4 + 5 = 4 + 3 + 5 = 12 cm.
Since volume term is not valid in case of triangles, so they cannot have equal volumes. Therefore, option (A) is incorrect.
Area of ΔABC is

and area of ΔDEF is

Therefore, they may have equal areas and so option (B) is correct.
If the triangles have equal bases, then the heights will also be equal and both the triangles will be same. Similar is the case with equal heights. So, options (C) and (D) are incorrect.
Thus, the correct option is (B). equal areas.