Answer:
Z and B are independent events because P(Z∣B) = P(Z).
Step-by-step explanation:
After a small online search, I've found a table to complete this problem, that we can see below.
For two events Z and B, we have:
P(Z|B) = probability of Z given that B
such that:
P(Z|B) = P(Z∩B)/P(B)
So, two events are independent if the outcome of one does not affect the outcome of the other.
So, if the probability of Z given B is different than P(Z) (the probability of event Z) means that the events are not independent.
So Z and B are independent if the probability of Z given B is equal to the probability of Z.
P(Z|B) = P(Z)
In the table we can see:
P(Z|B) will be equal to the quotient between all the cases of Z given B (126) and the total cases are given B (280)
P(Z|B) = 126/280 = 0.45
Similarly, we can find P(Z):
And P(Z) = 297/660 = 0.45
So we can see that:
P(Z|B) = P(Z)
Thus, B and Z are independent.
B.
Let's simply look at each conjecture and determine if it's true or false.
A. 2n– 1 is odd if n is positive: Since n is an integer, 2n will
always be even. And an even number minus 1 is always odd. Doesn't matter
if n is positive or not. So this conjecture is true.
B. 2n– 1 is always even: Once again, 2n will always be even. So 2n-1 will always be odd. This conjecture is false.
C. 2n– 1 is odd if n is even: 2n is always even, so 2n-1 will always
be odd, regardless of what n is. So this conjecture is true.
D. 2n– 1 is always odd: 2n will always be even. So 2n-1 will always be odd. Once again, this conjecture is true.
Of the 4 conjectures above, only conjecture B is false. So the answer is B.
Could be 21. Try replacing function designators with the actual functions.
Answer:

Step-by-step explanation:

Simplified becomes;

Simplifying further gives; 