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STatiana [176]
1 year ago
15

28 Jess bought a new car for £12 000.

Mathematics
1 answer:
devlian [24]1 year ago
7 0

The value of the car after three years is £6936

<h3>How to determine the value of the car?</h3>

The initial value of the car is given as:

Value =  £12000

When the value depreciates by 20% after the first year, the new value of the car is:

New =  £12000 * (1 - 20%)

Evaluate

New =  £9600

When the value depreciates by 15% after the second year, the new value of the car is:

New =  £9600* (1 - 15%)

Evaluate

New =  £8160

When the value depreciates by 15% after the third year, the new value of the car is:

New =  £8160 * (1 - 15%)

Evaluate

New =  £6936

Hence, the value of the car after three years is £6936

Read more about depreciation at:

brainly.com/question/25297296

#SPJ1

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How do you solve 9| x+8 | + 10 &lt; 55 &amp; how is it graphed
mafiozo [28]
Hello!

First, let's write the problem.
9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55
Subtract 10 from both sides.
9\left|x+8\right|+10-10\ \textless \ 55-10
9\left|x+8\right|\ \textless \ 45
Divide both sides by 9.
\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}
\left|x+8\right|\ \textless \ 5
When we got absolute value, we are going to get two results.
x+8\ \textless \ 5
and
x+8\ \textgreater \ -5

Let's solve the first one,
x+8\ \textless \ 5x+8\ \textless \ 5
Subtract 8 from both sides.
x+8-8\ \textless \ 5-8
x\ \textless \ -3x\ \textless \ -3

Let's solve the second one.
x+8\ \textgreater \ -5
Subtract 8 from both sides.
x+8-8\ \textgreater \ -5-8
x\ \textgreater \ -13x\ \textgreater \ -13

Let's combine the ranges.
-13\ \textless \ x\ \textless \ -3

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

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2 years ago
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Step-by-step explanation:

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3 years ago
Use the picture to answer the question.
tatyana61 [14]

Answer:

31.4cm

Step-by-step explanation:

C = 2π.r = 2×3.14×5 =3.14×10 = 31.4

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