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seropon [69]
2 years ago
12

If a student applied force 36N on a bench and it displaced by 4 m how much work did that student do

Mathematics
2 answers:
MAVERICK [17]2 years ago
8 0
<h3>Answer:  144 Joules </h3>

Steps Shown:

Work = Force * Displacement

Work = (36 Newtons)*(4 meters)

Work = (36*4) Newton meters

Work = 144 Newton meters

Work = 144 Joules

Note: The displacement must point in the same direction as the force applied.

castortr0y [4]2 years ago
5 0

Answer:

<em>The </em><em>answer</em><em> </em><em>is </em><em>1</em><em>4</em><em>4</em>

Step-by-step explanation:

Work Done = Force × Distance

W= F×D

F= 36N

D= 4m

W= 36×4

W= 144j

N/B The workdone is always in Joules.

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8

Step-by-step explanation:

(10-4)+20/20

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3 years ago
Susan needs to buy 3 helium balloons. She can buy individual balloons for $2.75 each, or a 3-pack of balloons for $7.80. How muc
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Answer:

15

Step-by-step explanation:

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8 0
3 years ago
The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
MatroZZZ [7]

Answer:

a. x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8

Step-by-step explanation:

Given that

8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9

Now

if one is added i.e.

2d^5 - c^3d^2 + 8cd^4 + 1

Now let us assume the other polynomial be x

So,

8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 = x  + (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\x = 8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\

x = (8d^5 - 2d^5) + (-3c^3d^2 + c^3d^2) + 5c^2d^3+ (-4cd^4-8cd^4) + (9-1)\\\\x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8

8 0
3 years ago
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Rewrite it in factored form: x4 - y2 x2
SCORPION-xisa [38]

Answer:

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Step-by-step explanation:

I'm going to write it so I can see it better:

x^4-y^2x^2

You can use the difference of squares formula:

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3 0
3 years ago
Triangle XYZ is rotated 90° counterclockwise about the origin.
sergeinik [125]

Answer:

i think 42

Step-by-step explanation:

4 0
3 years ago
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