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VLD [36.1K]
2 years ago
11

What is 12x³ – 9x² − 4x + 3 in factored form? Pls hurry

Mathematics
2 answers:
AleksandrR [38]2 years ago
8 0

Answer:

(3x^2 - 1)(4x - 3)

Step-by-step explanation:

We can use grouping to factor this

12x^3 – 9x^2 − 4x + 3

group into: (12x^3 – 9x^2)(− 4x + 3)

Solve one side at a time:

(12x^3 – 9x^2)

3x^2(4x - 3) factor out a 3x^2

(− 4x + 3)

- 1 (4x - 3) factor out a -1

put the two equations togeth

(3x^2 - 1)(4x + 3)

kumpel [21]2 years ago
6 0

Answer:

\bold{\green{(4x-3)(3x^{2}-1) }}

Step-by-step explanation:

  • \sf{12x^{3}-9x^{2}-4x+3 }

  • \sf{3x^{2}(4x-3)-1(4x-3) }

  • \sf{(4x-3)(3x^{2}-1) }
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Translate the following word phrase into an algebraic expression: six times four less than three times x
gulaghasi [49]

Answer:

Step-by-step explanation:

6(3x - 4)

4 0
3 years ago
Read 2 more answers
Celia sells calendars for fundraiser. Each calendar cost $9. She sells 16 calendars to her family members and 14 calendars to th
Sunny_sXe [5.5K]

Answer:

Since Her goal is to earn $ 300 , but now she is earning only $270 ,Hence Celia will not achieve her goal  .

Step-by-step explanation:

Given as :

The cost of each calendar = $ 9

The number of calendar sold to the family = 16

The number of calendar sold to the neighborhood = 14

So, Total number of calendar sold by Celia = The number of calendar sold to the family + The number of calendar sold to the neighborhood

i.e Total number of calendar sold by Celia = 16 + 14 = 30

∵ The cost of each calendar = $ 9

∴ The cost of 30 calendar = $ 9 × 30 = $ 270

Since Her goal is to earn $ 300 , but now she is earning only $270 ,Hence Celia will not achieve her goal  .  Answer

5 0
4 years ago
Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q
Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq              (*)


Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

sin(2q) =                      (**)

sinq*cosq + cosq*sinq      => as both terms are identical

2 sinq*cosq


Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

                          = 1 +  sin(2q)

Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

7 0
3 years ago
Round 6.487 and 2.049 to the hundredths place.<br><br> What is the sum of the rounded numbers?
sergey [27]

Hello there! 6.487 rounded to the nearest hundredths place is 6.49 and 2.049 rounded to the hundredths place is 2.05. The sum of these numbers is 8.54.

Remember: If the number value after the value you are rounding is equal to or greater than 5, round up. If it is less than 5, round down.

With this in mind, let's round the numbers:

First: 6.487 rounded to the hundredths place would be 6.49, since 7 is greater than 5.

Second: 2.049 rounded to the hundredths place would be 2.05, since 9 is greater than 5.

Next, we will add the numbers together

2.05 + 6.49 = 8.54.

So, this is our final answer. I hope this answers your question & have a great day! :)

3 0
4 years ago
Cho f(x, y) = x cos(xy). Tính f”xy(π2, −1)
Len [333]

because the cos(xu

y) so the formula have to be cos

4 0
3 years ago
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