We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in .
Let's try even though we are forbidden to put 4 inside
we are still able to do so.
So what we just got is the upper limit of the range. The lower limit is
.
So the range is just .
Hope this helps :)
Answer:
Step-by-step explanation:
(a) ∠FBM is the complement of ∠FBC, so is ...
∠FBM = 90° -52° = 38°
The measure of arc BF is twice this angle, so is ...
arc BF = 2∠FBM = 2(38°)
arc BF = 76°
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(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...
∠M = (1/2)(138° -76°) = 62°/2
∠M = 31°
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(c) arc FC is the supplement to arc BF, so has measure ...
arc FC = 180° -arc BF = 180° -76° = 104°
∠BGE is half the sum of arcs BE and FC, so is ...
∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2
∠BGE = 121°
__
(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...
∠MFB = 180° -∠M -∠FBM = 180° -31° -38°
∠MFB = 111°
Answer:
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The figure shows a kite
The kite has two pairs of consecutive and congruent sides and the diagonals are perpendicular
That means
TS=VS
TQ=VQ
TR=RV
we have
so
solve for x
<em>Find the value of RV</em>
substitute the value of x
Remember that
---> by segment addition postulate
we have
so
