The average power produced by the soccer player is 710 Watts.
Given the data in the question;
- Mass of the soccer player;

- Energy used by the soccer player;

- Time;

Power; 
Power is simply the amount of energy converted or transferred per unit time. It is expressed as:

We substitute our given values into the equation
![Power = \frac{5100000J}{7200s}\\\\Power = 708.33J/s \\\\Power = 710J/s \ \ \ \ \ [ 2\ Significant\ Figures]\\\\Power = 710W](https://tex.z-dn.net/?f=Power%20%3D%20%5Cfrac%7B5100000J%7D%7B7200s%7D%5C%5C%5C%5CPower%20%3D%20708.33J%2Fs%20%5C%5C%5C%5CPower%20%3D%20710J%2Fs%20%5C%20%5C%20%5C%20%5C%20%5C%20%5B%202%5C%20Significant%5C%20Figures%5D%5C%5C%5C%5CPower%20%3D%20710W)
Therefore, the average power produced by the soccer player is 710 Watts.
Learn more: brainly.com/question/20953664
Answer:Infrared light has a wavelength that is longer than that of standard red light, and although considered part of the red color spectrum, infrared wavelengths are still much shorter
Mass of gold m₁ = 47 g
Initial temperature of gold T₁ = 99 C
Specific heat of gold C₁ = 0.129 J/gC
final temperature T₂ = 38 C
Heat needed by the gold to cool down
Q =m₁ * C₁* ( T₁ - T₂)
Q = (47)(0.129)(99-38)
Q = 369.843 J
This heat will be given by the water
we need to find out mass of water m₂
and initial temperature of water is T₃ = 25 C
Specific heat of water C₂ = 4.184 J/gC
Q = m₂*C₂*(T₂ - T₃)
369.843 = m₂(4.184)(38-25)
m₂ = 6.8 g
Answer:
I = 1.38 A
Explanation:
Given that,
Charge, q = 5000 C
Time, t = 1 hour = 3600 s
We need to find the current intensity. The current intensity is equal to the electric charge per unit time. It can be given by :

Substitute all the values in the above formula

So, the current intensity is 1.38 A.