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SVETLANKA909090 [29]
3 years ago
6

A starlike object seen on deep sky photographs coincides with an intense radio source and has a spectrum in which the characteri

stic lyman pattern of hydrogen spectral lines has been shifted from the ultraviolet to the visible spectral range. what is this object?
Physics
1 answer:
liberstina [14]3 years ago
6 0
A quasar - <span>Quasars are very distant objects. They  are really bright masses of energy and light. The word quasar is actually short for quasi-stellar radio source or quasi-stellar object. This high amount of energy in such a small area can only be formed by matter falling towards a Black Hole. That's why quasars are believed to be huge black holes  in the center of young galaxies.
</span><span />
You might be interested in
PLEASE HELP ME ASAP!!!
maks197457 [2]
Answer:

<span>Plants that have been buried</span>

Explanation :

According to the provided graph it is showing that the plant dies and buried before  microbes which make them decay , then heat and pressure in Earth's crust for millions of years which can turn into coal,gas, or oil which then is extracted and burnt to create carbon dioxide in which a plant takes it in and the process repeats
4 0
3 years ago
Read 2 more answers
How far from a converging lens with a focal length of 16 cm should an object be placed to produce a real image which is the same
Feliz [49]

Answer:

32 cm

Explanation:

f = focal length of the converging lens = 16 cm

Since the lens produce the image with same size as object, magnification is given as

m = magnification = - 1

p = distance of the object from the lens

q = distance of the image from the lens

magnification is given as

m = - q/p

- 1 = - q/p

q = p                                    eq-1

Using the lens equation, we get

1/p + 1/q = 1/f

using eq-1

1/p + 1/p = 1/16

p = 32 cm

4 0
3 years ago
The doppler effect is when objects are not moving?<br><br> True <br><br> False
SVETLANKA909090 [29]

Answer:

reviewing the statement we can say that it is FALSE

Explanation:

The Doppler effect is the change in the perceived frequency of a sound wave by the RELATIVE MOTION of the source and the observer.

This effect is very useful for finding the speed of an object.

When reviewing the statement we can say that it is FALSE

6 0
3 years ago
1) Halving the distance (i.s., decreasing by a factor of two) between two charged objects will cause the electrical force betwee
Vedmedyk [2.9K]

Answer:

Explanation:

For an electric force, F the formula:

F = kQq/r^2

Given:

r2 = 1/2 × r1

F1 × r1 = k

F1 × r1 = F2 × r2

F2 = (F1 × r1^2)/(0.5 × r1)^2

= (F1 × r1^2)/0.25r1^2

= 4 × F1.

7 0
3 years ago
The velocity time graph of a car shown below a) Calculate the magnitude of displacement of the car in 40 seconds. b) During whic
Gekata [30.6K]

Answer:

a) 0 metres

b) From time 0 s to 10 s , the car was accelerated. Its velocity accelerated from 0m/s to 20 m/s

c) 20 m/s

Explanation:

a) <em>Formula of displacement= velocity x time</em>

time=40 s

velocity =0 m/s

∴ displacement= 0 x 40 = 0 m

Magnitude of displacement is 0 m

b) The increase in velocity shows that there has been acceleration.

c) The average velocity of the car is =\frac{0+40}{2\\}   {initial velocity + final velocity}

                                                            =\frac{40}{2}

                                                             =20

Therefore, the magnitude of the average velocity  of the car is 20 m/s

3 0
3 years ago
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