1. A. 6.00 sec
The graph shows the velocity of an object (y-axis) versus the time (x-axis). In order to find when the magnitude of the velocity reaches 36.00 km/h, we should find the time t (x-coordinate) at which the velocity (y-coordinate) is 36.
By looking at the graph, we see that this occurs when t=6.00 s.
2. A. positive acceleration
In a velocity-time graph like this one, the slope of the curve corresponds to the acceleration of the object. In fact, acceleration is defined as:
where 
is the variation of velocity and 
is the variation of time. We see that this quantity corresponds to the slope of the curve in the graph (in fact, represents the increment of the y coordinate, while represents the increment of the x coordinate). So, a positive slope means a positive acceleration: in this case, the slope is positive, so the acceleration is also positive.
Answer:
Explanation:
The final velocity is given by the following kinematic equation:
Here, 
is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:
Now, we calculate the final velocity:
Answer:
a) vB = 10.77 ft/s
b) W = 11.30 lb*ft
Explanation:
a) W = 8 lb ⇒ m = W/g = 8 lb/32.2 ft/s² = 0.2484 slug
vA <em>lin</em> = 5 ft/s
rA = 2 ft
v <em>rad</em> = 4 ft/s
vB = ?
rB = 1 ft
W = ?
We can apply The law of conservation of angular momentum
L<em>in</em> = L<em>fin</em>
m*vA*rA = m*vB*rB ⇒ vB = vA*rA / rB
⇒ vB = (5 ft/s)*(2 ft) / (1 ft) = 10 ft/s (tangential speed)
then we get
vB = √(vB tang² + vB rad²) ⇒ vB = √((10 ft/s)² + (4 ft/s)²)
⇒ vB = 10.77 ft/s
b) W = ΔK = K<em>B</em> - K<em>A</em> = 0.5*m*vB² - 0.5*m*vA²
⇒ W = 0.5*m*(vB² - vA²) = 0.5*0.2484 slug*((10.77 ft/s)²-(5 ft/s)²)
⇒ W = 11.30 lb*ft
Answer:
Ix,Iy,Iz = mr²,9mr²,10mr²
Explanation:
The Question has some missing details.
To solve this question, I'll make the following assumptions.
Distance of particle x = r
Distance of particle y = 3r
Given
The mass of each particles = m
The moment of inertia is calculated by adding product of mass” of each particle with the “square of its distance from the axis of the rotation”.
Ix = m * (r)² = mr²
Iy = m(3r)² = m * 9r² = 9mr²
The distance of z from the axis is r² + (3r)²
So, Iz = m(r² + (3r)²)
Iz = m(r² + 9r²)
Iz = m(10r²)
Iz = 10mr²
So, we have
Ix,Iy,Iz = mr²,9mr²,10mr²
Answer:
Resistance of A is 
and B is 
Explanation:
The voltage across both the resistances will be the same as they are connected in parallel.
V = Voltage = 6 V
Resistance is given by
Series connection
The current is constant in series connection
The resistance of A is and B is .
