Answer:
See the answers below
Explanation:
In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.
We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.
where:
W = weight [N] (units of Newtons)
m = mass = 15 [kg]
g = gravity acceleration [m/s²]
Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.
<u>Mercury</u>
<u />![w_{mercury} = 15*3.8\\w_{mercury}= 57 [N]\\](https://tex.z-dn.net/?f=w_%7Bmercury%7D%20%3D%2015%2A3.8%5C%5Cw_%7Bmercury%7D%3D%2057%20%5BN%5D%5C%5C)
<u />
<u>Venus</u>
<u />![w_{venus}=15*8.8\\w_{venus}= 132 [N]](https://tex.z-dn.net/?f=w_%7Bvenus%7D%3D15%2A8.8%5C%5Cw_%7Bvenus%7D%3D%20132%20%5BN%5D)
<u />
<u>Moon</u>
<u />![w_{moon}=15*1.6\\w_{moon}=24[N]](https://tex.z-dn.net/?f=w_%7Bmoon%7D%3D15%2A1.6%5C%5Cw_%7Bmoon%7D%3D24%5BN%5D)
<u />
<u>Mars</u>
![w_{mars}=15*3.7\\w_{mars}=55.5 [N]](https://tex.z-dn.net/?f=w_%7Bmars%7D%3D15%2A3.7%5C%5Cw_%7Bmars%7D%3D55.5%20%5BN%5D)
<u>Jupiter</u>
<u />![w_{jupiter}=15*23.1\\w_{jupiter}= 346.5[N]](https://tex.z-dn.net/?f=w_%7Bjupiter%7D%3D15%2A23.1%5C%5Cw_%7Bjupiter%7D%3D%20346.5%5BN%5D)
<u />
<u>Saturn</u>
<u />![w_{saturn}=15*9\\w_{saturn}=135[N]](https://tex.z-dn.net/?f=w_%7Bsaturn%7D%3D15%2A9%5C%5Cw_%7Bsaturn%7D%3D135%5BN%5D)
<u />
<u>Uranus</u>
<u />![w_{uranus}=15*8.7\\w_{uranus}=130.5[N]](https://tex.z-dn.net/?f=w_%7Buranus%7D%3D15%2A8.7%5C%5Cw_%7Buranus%7D%3D130.5%5BN%5D)
<u />
<u>Neptune</u>
<u />![w_{neptune}=15*11\\w_{neptune}=165[N]](https://tex.z-dn.net/?f=w_%7Bneptune%7D%3D15%2A11%5C%5Cw_%7Bneptune%7D%3D165%5BN%5D)
<u />
<u>Pluto</u>
<u />![w_{pluto}=15*0.6\\w_{pluto}=9[N]](https://tex.z-dn.net/?f=w_%7Bpluto%7D%3D15%2A0.6%5C%5Cw_%7Bpluto%7D%3D9%5BN%5D)
<u />
Answer: The acceleration due to gravity on the surface of the Moon is approximately 1.625 m/s2, about 16.6% that on Earth's surface or 0.166 ɡ.
Heres your answer.
If the weight of the metal disk is 1.0 N, the normal force acting on the metal disk is also 1.0 N but acting in the opposite direction.
<h3>What is the normal force?</h3>
According to Newton Law, action and reaction are equal and opposite. The reaction force is equal in magnitude to the weight of an object but opposite in direction.
Having said that, if the weight of the metal disk is 1.0 N, the normal force acting on the metal disk is also 1.0 N but acting in the opposite direction.
Learn more about normal force:brainly.com/question/18799790
#SPJ1
<span> An electroscope that might have a static charge is tested on a metal surface. From there, the charges move to the metal and straight to the foil leaves. If they repel, or move away from each other, that means they have identical charges. This applies for both positive and negative static electricity.
work cited: School of champions, Google
</span>
Answer:
Explanation:
Given,
mass = 1.41 g = 0.00141 Kg
Electric field,E = 670 N/C.
We know,
Force in charge due to Electric field.
F = E q
And also we know
F = m g
Equating both the equation of motion
m g = E q
Charge of the particle is equal to
