Two car collide in an intersection. The speed limit in that zone is 30 mph. The car (mass of 1250 kg) was going 17.4 m/s (38.9).
1 answer:
Answer:
u₂ = 3.7 m/s
Explanation:
Here, we use the law of conservation of momentum, as follows:
where,
m₁ = mass of the car = 1250 kg
m₂ = mass of the truck = 2020 kg
u₁ = initial speed of the car before collision = 17.4 m/s
u₂ = initial speed of the tuck before collision = ?
v₁ = final speed of the car after collision = 6.7 m/s
v₂ = final speed of the truck after collision = 10.3 m/s
Therefore,
<u>u₂ = 3.7 m/s</u>
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Answer:
The electric field strength inside the capacitor is 49880.77 N/C.
Explanation:
Given:
Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m
Separation between the plates (d) = 0.407 mm =
Energy stored in the capacitor (U) =
Assuming the medium to be air.
So, permittivity of space (ε) =
Area of the square plates is given as:
Capacitance of the capacitor is given as:
Now, we know that, the energy stored in a parallel plate capacitor is given as:
Rewriting in terms of 'E', we get:
Now, plug in the given values and solve for 'E'. This gives,
Therefore, the electric field strength inside the capacitor is 49880.77 N/C
The change in kinetic energy is
Explanation:
According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Mathematically:
where :
W is the work done on the object
is the final kinetic energy of the object
is the initial kinetic energy
Also, the work done on an object is (assuming that the force is applied parallel to the motion of the object):
where
F is the magnitude of the force
is the displacement of the object
In this problem, the force acting on the object is
F
While the displacement is the horizontal distance travelled, so
Therefore, the work done is
And so the change in kinetic energy is
Learn more about work and kinetic energy:
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