Step 1 : Get your supply list together
Step 2 : Pick what model you want to do
Step 3 : Ask for a partner 
Step 4 : Complete  the model and take your time.
Step 5 : Read the directions carefully 
        
             
        
        
        
Answer:
 The movement of an object depends on the reference frame, so it is important to predicate it. 
Explanation:
 
        
             
        
        
        
You would get 13.7 
mi/51mm=3.5mm/13mm
by solving it you will B13.7mm
        
                    
             
        
        
        
<span>Using conservation of energy and momentum you can solve this question. M_l = mass of linebacker 
M_ h = mass of halfback 
V_l = velocity of linebacker 
V_h = velocity of halfback 
So for conservation of momentum, 
rho = mv
M_l x V_li + M_h x V_hi = M_l x V_lf + M_h x V_hf 
For conservation of energy (kinetic) 
E_k = 1/2mv^2/ 1/2mV_li^2 + 1/2mV_{hi}^2 = 1/2mV_{lf}^2 + 1/2mV_{hf}^2 
Where i and h stand for initial and final values. 
We are already told the masses, \[M_l = 110kg\] \[M_h = 85kg\] and the final velocities \[V_{fi} = 8.5ms^{-1}\] and \[V_{ih} = 7.2ms^{-1} </span>
        
             
        
        
        
Answer:
a). 6 seconds
b). 12 seconds
c). 176.4 meters
Explanation:
a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,
    v = u - gt
where v = final velocity
u = initial velocity = 58.8 m per sec
g = gravitational pull = 9.8 m per sec²
t = duration of the flight 
At the peak height, 
v = 0
Therefore, 0 = 58.8 - (9.8)(t)
t =  
  = 6 seconds
b). Total time of flight = 2(Time taken to go up)
                                     = 2×6 
                                     = 12 sec
c). Formula to get the peak height is,
    
    h = (58.8)6 - 
       = 352.8 - 176.4
       = 176.4 meters