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Gekata [30.6K]
2 years ago
13

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

screen 5 ft from a light is 2 foot-candles, find the intensity on a screen 20 ft from the light
Physics
1 answer:
emmasim [6.3K]2 years ago
6 0

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\  I_2= 0.125 \ foot-candles

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

#SPJ1

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A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

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V_{f} \approx 0.996\,m^{3}

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\Delta V = V_{o} - V_{f}

\Delta V = 1\,m^{3} - 0.996\,m^{3}

\Delta V = 0.004\,m^{3}

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

8 0
3 years ago
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