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3 years ago

What precautions should be taken on board a vessel during a lightning storm?

Physics

2 answers:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

When huge amount of electrical discharge occurs from the atmosphere, a lightning storm is said to occur.

Following precautions must be taken if one is on board a vessel during a lightning storm:

During a lightning storm, all the plugs should be disconnected and electrical appliances must be switched off.
One should remain inside the cabin and not move outside because the charges remain on the surface of a conductor.
The movement should be avoided. It would be best to lay straight down.

dusya [7]3 years ago

7 0

The precautions which should be taken on board a vessel during a lightning storm are:

(i) All electrical equipments should be unplugged.

(ii) Keep yourself away from all metal parts such as engines, metal tanks, stoves etc.

(iii) Stay inside the boat.

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n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend

Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

$p_f=p_i\\mv_1+Mv_2=(m+M)v$

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

$(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}$

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

$E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2$

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

$(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m$

hence, the heigth is 68cm

4 0

3 years ago

How fast (in rpm) must a centrifuge rotate if a particle 7.50 cm from the axis of rotation is to experience an acceleration of 1

Andreas93 [3]

Explanation:

Below is an attachment containing the solution.

7 0

3 years ago

Which of the following is most likely not a case of uniform circular motion

Ivan

Answer:

Motion of a racing car on a circular track

Explanation:

Uniform circular motion means the motion of the object is in a circle with a CONSTANT SPEED.

The racing car will accelerate during its motion. Hence, it is not a uniform circular motion.

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2 years ago

1. Describe what is happening at point A when these 3 vectors act on point A. 2. Describe what happen to the resultant vector at

zavuch27 [327]

Answer: Don't know sorry

Explanation:

4 0

2 years ago

A bullet B of mass mB traveling with a speed v0 = 1400 m/s ricochets off a fixed steel plate A of mass mA. Let mA ≫ mB so that i

Greeley [361]

Answer:

Rebounce angle is 345°

Rebounce speed is 989.95m/s

Explanation:

Calculate the x component of the velocity of the bullet before impact by using the following relation:

Vbx= Vb Cos thetha

Here, is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°

Substituting

Vbx = Cos15 ×1400 = 1352.30m/s

Calculate the y component using the relation:

Vby = Vo Sin theta

Vby = sin 15° × 1400

Vby = 362.35m/s

The rebounce angle = 360 - incidence angle

Rebounce angle =( 360 - 15)° = 345°

The rebound speed V' = Vby - Vbx

V' = (1352.30 - 362.35)m/s

V' = 989.95 m/s

5 0

3 years ago