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Ierofanga [76]
2 years ago
11

Let x²y +ay² = b be an Implicitly defined function, where a and b are fixed Constants; find dy/dx

Mathematics
1 answer:
geniusboy [140]2 years ago
3 0

The value of the differential with respect to x is -xy/x²+ay

<h3>Implicit differentiation</h3>

Given the following function

x²y +ay² = b

We are to differentiate implicitly with respect to x

x²dy/dx + 2xy + 2aydy/dx = 0

(2x²+2ay)dy/dx = -2xy
dy/dx = -xy/x²+ay

Hence the value of the differential with respect to x is -xy/x²+ay

Learn more on implicit differentiation here: brainly.com/question/25081524

#SPJ1

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Step-by-step explanation:

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82% certain the answer you're looking for is 4  2/9π (<em>pi symbol because it asks for it in terms of pi)</em>

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In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
Mademuasel [1]

Answer:  7\frac{5}{7} unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

∠PDC ≅ ∠PAB ( because DC ║ AB )

And, ∠ PAB ≅ ∠ PBA

∠DPC ≅ ∠ APB ( reflexive)

Therefore, By AAA similarity postulate,

\triangle PDC \sim \triangle PAB

Thus, By the definition of similarity,

\frac{PD}{PA} = \frac{DC}{AB}

\frac{PD}{PD+3} = \frac{11}{18} ( because PA = PD+DA)

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⇒7PD = 33

⇒ PD = 33/7

Again by the definition of similarity,

\frac{PC}{PB} = \frac{DC}{AB}

\frac{PC}{PC+7} = \frac{11}{18} ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA =  PD+DA = 33/7 + 3 = 7\frac{5}{7}

And, PB = PC + CB = 11 + 7 = 18


8 0
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