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hram777 [196]
2 years ago
15

Begin by graphing the standard absolute value function f(x) = | x |. Then use transformations of this graph to describe the grap

h the given function.
g(x)=|x|+3
Mathematics
1 answer:
denpristay [2]2 years ago
6 0

Using translation concepts, it is found that the graph of g(x) is a shift up of 3 units of the graph of f(x).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the functions are:

  • f(x) = |x|.
  • g(x) = |x| + 3 = f(x) + 3.

That is, the graph of g(x) is a shift up of 3 units of the graph of f(x), as shown at the end of this problem in the graph.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

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Elza [17]

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6 0
3 years ago
URGENT!!! 50 POINTS!!! URGENT!!!!!!! Consider the polynomial functions P (x) and Q (x)​ , where neither polynomial is a constant
Nutka1998 [239]

Answer:

Always

Always

Sometimes

Never

Step-by-step explanation:

P(X) + Q(X)

Sum of two polynomials is always a polynomial.

For example, Let P(x) = 3x² and Q(x) = 5x

$ \implies P(x) + Q(x) = 3x² + 5x

This is again a polynomial.

In other words, we can say that Polynomial is closed under addition.

P(x) . Q(x)

Product of two polynomials is again a polynomial.

Let P(x) = 2x and Q(x) = a constant function, 5

Then the product = 10x, is again a polynomial.

Multiplication of two polynomials is closed.

P(x) / Q(x)

This need not always be a polynomial. When Q(x) = a constant function zero, i.e., Q(x) = 0, then the function is not defined.

But let's say P(x) = 5x² and Q(x) = x.

$ \frac{P(x)}{Q(x)} $ = $ \frac{5x^2}{x} $ = 5x, a polynomial.

So, $ \frac{P(x)}{Q(x)} $ is a polynomial sometimes.

We can, say Division is not always closed.

1/Q(x)

This could never be a polynomial. This is not even in the form of a polynomial. So, $ \frac{1}{Q(x)} $ is never a polynomial.

Hence, the answer.

7 0
3 years ago
The volume of a cylinder is 156 x cm3. What is the volume of a cone with the same base and height as the cylinder?
Flura [38]

Answer: SECOND OPTION (52 cm³)

Step-by-step explanation:

The formula for calculate the volume of a cone is:

V{co}=\frac{1}{3}r^{2}h\pi

Where r is the radius and h is the height.

 The formula for calculate the volume of a cylinder is:

V{cy}=r^{2}h\pi

Where r is the radius and h is the height.

As you can see, the difference between the the formulas is that r²hπ of the cone is divided by 3. Therefore, if you know the volume of the cylinder and you know that the cone has the same base and height as the cylinder, you have to divide the volume of the cylinder by 3 to obtain the volume of the cone.

Therefore, the result is:

V{co}=\frac{156cm^3}{3}=52cm^3

7 0
3 years ago
Read 2 more answers
Michelle made 26 more sales calls last month than Allen. Together, they made 120 calls. How many calls were made by Michelle?
algol13

Answer

73

Step-by-step explanation:

you need to subtract the 26 from 120 to get 94 divide that by 2 to get 47 so thats haw many calls they each made then add on the 26 to find her amount to get 73

6 0
3 years ago
What is the rate of decay for the function f(x) =2(0.95)^x ( x is on top of the parentheses)
SIZIF [17.4K]

Answer:

The decay rate is 5%.

Step-by-step explanation:

Let a substance is decaying at the rate of r% per hour from the initial value of P for t hours, then the final value of the substance is given by the function  

f(t) = P(1 - \frac{r}{100})^{t} ........... (1)

Comparing this equation with the original equation given as

f(x) = 2(0.95)^{x} ............ (2) we get,

(1 - \frac{r}{100}) = 0.95

⇒ \frac{r}{100} = 0.05

⇒ r = 5%.

Therefore, the decay rate is 5%. (Answer)

7 0
4 years ago
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