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Aneli [31]
2 years ago
5

Please help. Show with steps please. Solve the compound inequality. 0 < 5-2x/3 <5

Mathematics
1 answer:
REY [17]2 years ago
7 0

Answer: The answer is x < 5/2 and x > -5.

Step-by-step explanation:

First you need to separate the inequality and keep x on one side to maintain consistency. For instance the problem-

\frac{5-2x}{3} > 0\\\frac{5-2x}{3} < 5\\

Now solve as normal.

*Note: When dividing a side or multiplying a side by a negative number, the sign of the inequality switches (this will be shown when I do the equation if it doesn't make since how I word it).

5-2x > 0*3\\5-2x < 5*3

-2x > 0-5\\-2x < 15-5

x < \frac{-5}{-2} =x < \frac{5}{2} \\x > \frac{10}{-2} =x > -5

So, x < 5/2 and x > -5.

<em>If anything is confusing about the procedure just leave a comment, and I'll try to explain further.</em>

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